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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.16b

Finding Antiderivatives
In Exercises 1–16, find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation.
4 sec 3x tan 3x

Verified step by step guidance
1
Identify the function to find the antiderivative of: \(\sec^3(3x) \tan(3x)\).
Recall that the derivative of \(\sec(x)\) is \(\sec(x) \tan(x)\), and the derivative of \(\sec^n(x)\) involves powers of \(\sec(x)\) and \(\tan(x)\).
Use substitution: let \(u = 3x\), so \(du = 3 \, dx\) or \(dx = \frac{du}{3}\).
Rewrite the integral in terms of \(u\): \(\int \sec^3(u) \tan(u) \cdot \frac{du}{3}\).
Recognize that \(\frac{1}{3}\) is a constant factor and the integral becomes \(\frac{1}{3} \int \sec^3(u) \tan(u) \, du\). Then, use the substitution \(w = \sec(u)\), so \(dw = \sec(u) \tan(u) \, du\), to express the integral in terms of \(w\) and integrate.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Antiderivatives (Indefinite Integrals)

An antiderivative of a function is another function whose derivative equals the original function. Finding antiderivatives involves reversing differentiation, often represented as indefinite integrals with a constant of integration. This process helps solve problems involving accumulation and area under curves.
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Trigonometric Functions and Their Derivatives

Understanding the derivatives of trigonometric functions like secant and tangent is essential. For example, the derivative of tan(x) is sec²(x), and the derivative of sec(x) is sec(x)tan(x). Recognizing these relationships aids in finding antiderivatives involving products of trig functions.
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Integration Techniques: Substitution and Product Rule Reversal

When integrating products of functions, techniques like substitution or recognizing derivatives of products (reverse product rule) are useful. For instance, if the integrand resembles the derivative of a product of functions, identifying this can simplify finding the antiderivative.
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