Ch. 6 - Applications of Integration

Briggs - Calculus: Early Transcendentals 3rd Edition

Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook

Briggs 3rd Edition

Ch. 6 - Applications of Integration

Problem 6.1.3a

Chapter 6, Problem 6.1.3a

Given the velocity function of an object moving along a line, explain how definite integrals can be used to find the displacement of the object.

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Understand that the velocity function \(v(t)\) gives the rate of change of the object's position with respect to time, i.e., \(v(t) = \frac{ds}{dt}\), where \(s(t)\) is the position function.

Recall that displacement over a time interval \([a, b]\) is the change in position, which can be found by integrating the velocity function over that interval.

Set up the definite integral of the velocity function from \(a\) to \(b\): \(\int_{a}^{b} v(t) \, dt\).

Interpret this integral as the net area under the velocity curve between \(t = a\) and \(t = b\), where areas above the time-axis contribute positively and areas below contribute negatively to displacement.

Evaluate the definite integral to find the displacement, which represents how far and in what direction the object has moved from time \(a\) to time \(b\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Velocity Function

The velocity function describes the rate of change of an object's position with respect to time. It can be positive or negative, indicating direction along a line. Understanding velocity is essential because it directly relates to how the position changes over time.

Definite Integral as Net Change

A definite integral of a velocity function over a time interval calculates the net change in position, or displacement. It sums the signed areas under the velocity curve, accounting for direction, thus providing the overall movement from start to end time.

Displacement vs. Distance

Displacement is the net change in position, which can be positive, negative, or zero, depending on direction. It differs from total distance traveled, which sums all movement regardless of direction. Definite integrals of velocity yield displacement, not total distance.

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