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Ch 09: Work and Kinetic Energy
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 9, Problem 47

A pile driver lifts a 250 kg weight and then lets it fall onto the end of a steel pipe that needs to be driven into the ground. A fall from an initial height of 1.5 m drives the pipe in 35 cm. What is the average force that the weight exerts on the pipe?

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Step 1: Identify the given values. The mass of the weight is \( m = 250 \, \text{kg} \), the initial height is \( h = 1.5 \, \text{m} \), and the distance the pipe is driven into the ground is \( d = 0.35 \, \text{m} \). The goal is to find the average force exerted on the pipe.
Step 2: Calculate the gravitational potential energy of the weight before it falls using the formula \( E_p = m g h \), where \( g \) is the acceleration due to gravity (\( g = 9.8 \, \text{m/s}^2 \)). This energy is converted into work done on the pipe.
Step 3: Relate the work done to the average force exerted on the pipe. The work-energy principle states that \( W = F_{\text{avg}} \cdot d \), where \( W \) is the work done, \( F_{\text{avg}} \) is the average force, and \( d \) is the distance the pipe is driven into the ground.
Step 4: Substitute \( W = E_p \) into the work formula. This gives \( F_{\text{avg}} = \frac{E_p}{d} \). Replace \( E_p \) with \( m g h \) to get \( F_{\text{avg}} = \frac{m g h}{d} \).
Step 5: Plug in the known values \( m = 250 \, \text{kg} \), \( g = 9.8 \, \text{m/s}^2 \), \( h = 1.5 \, \text{m} \), and \( d = 0.35 \, \text{m} \) into the formula \( F_{\text{avg}} = \frac{m g h}{d} \) to calculate the average force exerted on the pipe.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gravitational Potential Energy

Gravitational potential energy (GPE) is the energy an object possesses due to its height above the ground. It is calculated using the formula GPE = mgh, where m is mass, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height. In this scenario, the weight of the pile driver has GPE when lifted, which is converted to kinetic energy as it falls.
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Kinetic Energy and Impact Force

Kinetic energy (KE) is the energy of an object in motion, given by the formula KE = 0.5mv², where m is mass and v is velocity. When the weight falls and strikes the pipe, its kinetic energy is transferred to the pipe, causing it to move. The average force exerted on the pipe can be determined by analyzing the change in kinetic energy and the distance over which the force acts.
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Newton's Second Law of Motion

Newton's Second Law states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). This principle is crucial for calculating the average force exerted by the weight on the pipe, as it relates the net force to the mass of the falling weight and the deceleration experienced by the pipe as it is driven into the ground.
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Related Practice
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A 150 g particle at x = 0 is moving at 2.00 m/s in the + x - direction. As it moves, it experiences a force given by Fₓ = (0.250 N) sin (x/2.00 m). What is the particle's speed when it reaches x = 3.14 m?

Textbook Question

Susan's 10 kg baby brother Paul sits on a mat. Susan pulls the mat across the floor using a rope that is angled 30° above the floor. The tension is a constant 30 N and the coefficient of friction is 0.20. Use work and energy to find Paul's speed after being pulled 3.0 m.

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Textbook Question

A 50 kg ice skater is gliding along the ice, heading due north at 4.0 m/s. The ice has a small coefficient of static friction, to prevent the skater from slipping sideways, but μk = 0. Suddenly, a wind from the northeast exerts a force of 4.0 N on the skater. Use work and energy to find the skater's speed after gliding 100 m in this wind.