Skip to main content
Ch 04: Kinematics in Two Dimensions
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 4, Problem 59c

A cannonball is fired at 100 m/s from a barrel tilted upward at 25°. What is the angle after the cannonball travels 500 m?

Verified step by step guidance
1
Step 1: Recognize that the problem involves projectile motion. The angle after the cannonball travels 500 m refers to the angle of the velocity vector relative to the horizontal at that point in its trajectory.
Step 2: Break the initial velocity into horizontal and vertical components using trigonometric functions. The horizontal velocity component is \( v_x = v \cdot \cos(\theta) \), and the vertical velocity component is \( v_y = v \cdot \sin(\theta) \), where \( v = 100 \, \text{m/s} \) and \( \theta = 25^\circ \).
Step 3: Use the kinematic equation for vertical motion to find the vertical velocity \( v_y \) at the point where the cannonball has traveled 500 m horizontally. The equation is \( v_y = v_{y0} - g \cdot t \), where \( v_{y0} \) is the initial vertical velocity, \( g \) is the acceleration due to gravity (\( 9.8 \; \text{m/s}^2 \)), and \( t \) is the time of flight. To find \( t \), use the horizontal motion equation \( x = v_x \cdot t \), where \( x = 500 \; \text{m} \).
Step 4: Once \( v_x \) and \( v_y \) are determined, calculate the angle \( \phi \) of the velocity vector relative to the horizontal using the formula \( \tan(\phi) = \frac{v_y}{v_x} \). Solve for \( \phi \) using \( \phi = \arctan\left(\frac{v_y}{v_x}\right) \).
Step 5: Interpret the result. The angle \( \phi \) represents the direction of the cannonball's velocity vector relative to the horizontal after it has traveled 500 m horizontally. This angle will be less than the initial firing angle of 25° due to the effects of gravity on the vertical component of velocity.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
13m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Projectile Motion

Projectile motion refers to the motion of an object that is launched into the air and is subject to gravitational forces. It can be analyzed by breaking it into horizontal and vertical components, allowing us to predict the object's trajectory, range, and time of flight. Understanding the principles of projectile motion is essential for solving problems involving objects like cannonballs.
Recommended video:
Guided course
04:44
Introduction to Projectile Motion

Initial Velocity Components

The initial velocity of a projectile can be divided into horizontal and vertical components using trigonometric functions. For a cannonball fired at an angle, the horizontal component is found using cosine, while the vertical component is found using sine. These components are crucial for determining the projectile's path and position at any given time.
Recommended video:
Guided course
05:53
Calculating Velocity Components

Angle of Projection

The angle of projection is the angle at which an object is launched relative to the horizontal. It significantly affects the range and height of the projectile. In this problem, understanding how the angle changes as the cannonball travels is key to determining its position after covering a specific distance, such as 500 m.
Recommended video:
Guided course
01:04
Critical Angle
Related Practice
Textbook Question

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 60 m away, making a 30° angle with the ground. How fast was the arrow shot?

1
views
Textbook Question

While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38° with the vertical. While driving back home moments later at the same speed but in the opposite direction, you see that the rain is falling straight down. From these observations, determine the speed and angle of the raindrops relative to the ground.

1
views
Textbook Question

You're 6.0 m from one wall of the house seen in FIGURE P4.55. You want to toss a ball to your friend who is 6.0 m from the opposite wall. The throw and catch each occur 1.0 m above the ground. At what angle should you toss the ball?

3
views
Textbook Question

The angular velocity of a spinning gyroscope is measured every 0.5 s. The results and the best-fit line from a spreadsheet are shown in FIGURE P4.63. What is the gyroscope's initial angular velocity at t = 0 s?

1
views
Textbook Question

Ships A and B leave port together. For the next two hours, ship A travels at 20 mph in a direction 30° west of north while ship B travels 20° east of north at 25 mph. What is the speed of ship A as seen by ship B?

1
views
Textbook Question

A ball is thrown toward a cliff of height h with a speed of 30 m/s and an angle of 60° above horizontal. It lands on the edge of the cliff 4.0 s later. What is the ball's impact speed?

1
views