Predict the product when the dihydroxybenzene shown is treated with a single equivalent of both base and haloalkane.
Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring

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Mullins 1st Edition
Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring
Problem 18d
Mullins 1st Edition
Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring
Problem 18dChapter 23, Problem 18d
Predict the product of the following substitution/addition reactions involving phenoxides. [Because this problem represents a review of current and previous material, section numbers have been provided for your reference.]
(d) 
Verified step by step guidance1
Step 1: Analyze the reactants. The first reactant is phenol (C6H5OH), which can form phenoxide ions when treated with a strong base like NaOH. The second reactant is 4-bromo-3-nitrobenzoyl chloride, which contains an electrophilic carbonyl group and a bromine atom attached to the aromatic ring.
Step 2: Understand the role of NaOH. NaOH will deprotonate the phenol to form the phenoxide ion (C6H5O⁻), which is a strong nucleophile. This nucleophile can attack electrophilic centers in the second reactant.
Step 3: Identify the electrophilic site in the second reactant. The carbonyl carbon in the benzoyl chloride group is highly electrophilic due to the electron-withdrawing effects of the nitro group and the chlorine atom. This makes it susceptible to nucleophilic attack by the phenoxide ion.
Step 4: Predict the mechanism. The phenoxide ion will attack the carbonyl carbon of the benzoyl chloride group, leading to the formation of a tetrahedral intermediate. The chloride ion (Cl⁻) will then leave, resulting in the formation of an ester bond between the phenoxide and the benzoyl group.
Step 5: Consider the final product. The substitution reaction will yield a compound where the phenoxide group is attached to the benzoyl group, forming an ester. The bromine and nitro groups on the aromatic ring remain unchanged.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Phenoxide Ion
A phenoxide ion is formed when phenol (C6H5OH) loses a proton (H+) from its hydroxyl group, resulting in a negatively charged ion (C6H5O-). This ion is a strong nucleophile due to the resonance stabilization provided by the aromatic ring, making it highly reactive in substitution and addition reactions.
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Nucleophilic Aromatic Substitution (NAS)
Nucleophilic aromatic substitution is a reaction where a nucleophile replaces a leaving group on an aromatic ring. This process is facilitated by the presence of electron-withdrawing groups, such as nitro (NO2) or halogens, which stabilize the negative charge in the intermediate Meisenheimer complex, allowing the nucleophile to attack the aromatic system.
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Reactivity of Aromatic Compounds
Aromatic compounds exhibit unique reactivity patterns due to their stable resonance structures. The presence of substituents can significantly influence the reactivity; electron-donating groups enhance nucleophilicity, while electron-withdrawing groups can facilitate nucleophilic attacks. Understanding these effects is crucial for predicting the outcomes of reactions involving aromatic systems.
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Related Practice
Textbook Question
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Textbook Question
Predict the product of the following substitution/addition reactions involving phenoxides.
(a)
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Textbook Question
Assessment 24.22 asked why meta-dihydroxybenzene could not be oxidized to meta-quinone. The attempted oxidation instead gives rise to three different quinone products. Suggest a mechanism for the formation of each.
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Textbook Question
(a) Based on Figure 24.23, explain why meta-dihydroxybenzene is not oxidized to meta-quinone.
(b) If a meta-quinone is not produced, what would you expect the product of the oxidation of meta-dihydroxybenzene to be?
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Textbook Question
In light of Figure 24.22, provide a mechanism by which para-dihydroxybenzene is oxidized to para-quinone.
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Textbook Question
Suggest a phenoxide and an alkyl halide to make the following aryl alkyl ethers.
(b)
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