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Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring
Mullins - Organic Chemistry: A Learner Centered Approach 1st Edition
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Not the one you use?Change textbook
Chapter 23, Problem 18d

Predict the product of the following substitution/addition reactions involving phenoxides. [Because this problem represents a review of current and previous material, section numbers have been provided for your reference.]
(d) Chemical reaction diagram showing phenoxide and brominated compound reacting with sodium hydroxide and water.

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1
Step 1: Analyze the reactants. The first reactant is phenol (C6H5OH), which can form phenoxide ions when treated with a strong base like NaOH. The second reactant is 4-bromo-3-nitrobenzoyl chloride, which contains an electrophilic carbonyl group and a bromine atom attached to the aromatic ring.
Step 2: Understand the role of NaOH. NaOH will deprotonate the phenol to form the phenoxide ion (C6H5O⁻), which is a strong nucleophile. This nucleophile can attack electrophilic centers in the second reactant.
Step 3: Identify the electrophilic site in the second reactant. The carbonyl carbon in the benzoyl chloride group is highly electrophilic due to the electron-withdrawing effects of the nitro group and the chlorine atom. This makes it susceptible to nucleophilic attack by the phenoxide ion.
Step 4: Predict the mechanism. The phenoxide ion will attack the carbonyl carbon of the benzoyl chloride group, leading to the formation of a tetrahedral intermediate. The chloride ion (Cl⁻) will then leave, resulting in the formation of an ester bond between the phenoxide and the benzoyl group.
Step 5: Consider the final product. The substitution reaction will yield a compound where the phenoxide group is attached to the benzoyl group, forming an ester. The bromine and nitro groups on the aromatic ring remain unchanged.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Phenoxide Ion

A phenoxide ion is formed when phenol (C6H5OH) loses a proton (H+) from its hydroxyl group, resulting in a negatively charged ion (C6H5O-). This ion is a strong nucleophile due to the resonance stabilization provided by the aromatic ring, making it highly reactive in substitution and addition reactions.
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Nucleophilic Aromatic Substitution (NAS)

Nucleophilic aromatic substitution is a reaction where a nucleophile replaces a leaving group on an aromatic ring. This process is facilitated by the presence of electron-withdrawing groups, such as nitro (NO2) or halogens, which stabilize the negative charge in the intermediate Meisenheimer complex, allowing the nucleophile to attack the aromatic system.
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Reactivity of Aromatic Compounds

Aromatic compounds exhibit unique reactivity patterns due to their stable resonance structures. The presence of substituents can significantly influence the reactivity; electron-donating groups enhance nucleophilicity, while electron-withdrawing groups can facilitate nucleophilic attacks. Understanding these effects is crucial for predicting the outcomes of reactions involving aromatic systems.
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