Skip to main content
Ch. 2 - Functions and Graphs
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
All textbooksBlitzer 8th EditionCh. 2 - Functions and GraphsProblem 84
Chapter 3, Problem 84

In Exercises 82–84, find f + g, f - g, fg, and f/g. Determine the domain for each function. f(x) = √(x + 7), g(x) = √(x - 2)

Verified step by step guidance
1
Step 1: Understand the problem. You are tasked with finding the sum (f + g), difference (f - g), product (fg), and quotient (f/g) of the functions f(x) = √(x + 7) and g(x) = √(x - 2). Additionally, you need to determine the domain for each resulting function.
Step 2: To find f + g, add the two functions: (f + g)(x) = √(x + 7) + √(x - 2). The domain of this function is determined by the intersection of the domains of f(x) and g(x). For f(x), the domain is x ≥ -7 (since the square root requires non-negative values). For g(x), the domain is x ≥ 2. The intersection of these domains is x ≥ 2.
Step 3: To find f - g, subtract the two functions: (f - g)(x) = √(x + 7) - √(x - 2). The domain is the same as for f + g, which is x ≥ 2, because the square root functions must remain defined.
Step 4: To find fg, multiply the two functions: (fg)(x) = √(x + 7) * √(x - 2). The domain is again the intersection of the domains of f(x) and g(x), which is x ≥ 2.
Step 5: To find f/g, divide the two functions: (f/g)(x) = √(x + 7) / √(x - 2). In addition to the domain restrictions from f(x) and g(x), you must exclude any x-values that make the denominator zero. Since g(x) = √(x - 2), the denominator is zero when x = 2. Therefore, the domain of f/g is x > 2.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
5m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Function Operations

Function operations involve combining two functions through addition, subtraction, multiplication, or division. For example, if f(x) and g(x) are two functions, f + g means adding their outputs, while f - g means subtracting the output of g from f. Understanding these operations is essential for manipulating and analyzing functions in algebra.
Recommended video:
7:24
Multiplying & Dividing Functions

Domain of a Function

The domain of a function is the set of all possible input values (x-values) for which the function is defined. For functions involving square roots, like f(x) = √(x + 7) and g(x) = √(x - 2), the expressions under the square roots must be non-negative. Identifying the domain is crucial for ensuring that the operations performed on the functions yield valid results.
Recommended video:
3:51
Domain Restrictions of Composed Functions

Composite Functions

Composite functions are formed when one function is applied to the result of another function. In the context of the given functions f and g, operations like f/g require understanding how the output of g affects the input of f. This concept is important for determining the overall behavior and restrictions of the resulting function, especially regarding its domain.
Recommended video:
4:56
Function Composition
Related Practice
Textbook Question

If one point on a line is (2, −6) and the line's slope is -3/2, find the y-intercept.

Textbook Question

Find f + g, f - g, fg, and f/g. f(x) = x2 + x + 1, g(x) = x2 -1

1
views
Textbook Question

In Exercises 77–92, use the graph to determine a. the function's domain; b. the function's range; c. the x-intercepts, if any; d. the y-intercept, if any; and e. the missing function values, indicated by question marks, below each graph.

Textbook Question

Begin by graphing the absolute value function, f(x) = |x|. Then use transformations of this graph to graph the given function. g(x) = |x+3|

Textbook Question

Use the graphs of f and g to solve Exercises 83–90.

Find (f+g)(−3).

Textbook Question

Use the graphs of f and g to solve Exercises 83–90.

Find (g-f) (-2).

1
views