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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.3.25

In Exercises 7–26, find the derivative of y with respect to x, t, or θ, as appropriate.
y = ∫(from 0 to lnx) sin(e^t) dt

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Identify the function given: \( y = \int_0^{\ln x} \sin(e^t) \, dt \). This is a definite integral with a variable upper limit \( \ln x \).
Recall the Fundamental Theorem of Calculus Part 1, which states that if \( y = \int_a^{g(x)} f(t) \, dt \), then \( \frac{dy}{dx} = f(g(x)) \cdot g'(x) \).
In this problem, \( f(t) = \sin(e^t) \) and the upper limit is \( g(x) = \ln x \). The lower limit is a constant (0), so it does not affect the derivative.
Compute the derivative of the upper limit: \( \frac{d}{dx} (\ln x) = \frac{1}{x} \).
Apply the chain rule: \( \frac{dy}{dx} = \sin(e^{\ln x}) \cdot \frac{1}{x} \). Note that \( e^{\ln x} = x \), so the derivative simplifies to \( \frac{dy}{dx} = \sin(x) \cdot \frac{1}{x} \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Fundamental Theorem of Calculus

This theorem connects differentiation and integration, stating that if a function is defined as an integral with a variable upper limit, its derivative is the integrand evaluated at that limit. It allows us to differentiate an integral with variable limits directly.
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Fundamental Theorem of Calculus Part 1

Chain Rule

The chain rule is used to differentiate composite functions. When the upper limit of the integral is a function of x (like ln(x)), we must multiply the derivative of the integral's upper limit by the derivative of that function to find the overall derivative.
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Intro to the Chain Rule

Properties of Logarithmic and Exponential Functions

Understanding the derivatives of ln(x) and e^t is essential here. The derivative of ln(x) is 1/x, and e^t is its own derivative. These properties help simplify the expression when applying the chain rule and evaluating the integrand.
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