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Ch. 11 - Parametric Equations and Polar Coordinates
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 11, Problem 11.PE.17

Lengths of Curves


Find the lengths of the curves in Exercises 13–19.


x = 5 cos t − cos 5t, y = 5 sin t − sin 5t, 0 ≤ t ≤ π/2

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1
Recall the formula for the length of a parametric curve given by \(x = x(t)\) and \(y = y(t)\) over the interval \(a \leq t \leq b\) is: \[L = \int_a^b \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt\]
Identify the given functions: \[x(t) = 5 \cos t - \cos 5t\] \[y(t) = 5 \sin t - \sin 5t\] and the interval is \(0 \leq t \leq \frac{\pi}{2}\).
Compute the derivatives \(\frac{dx}{dt}\) and \(\frac{dy}{dt}\): For \(x(t)\), use the derivative of cosine: \[\frac{dx}{dt} = -5 \sin t + 5 \sin 5t\] For \(y(t)\), use the derivative of sine: \[\frac{dy}{dt} = 5 \cos t - 5 \cos 5t\]
Substitute these derivatives into the arc length formula under the square root: \[L = \int_0^{\frac{\pi}{2}} \sqrt{\left(-5 \sin t + 5 \sin 5t\right)^2 + \left(5 \cos t - 5 \cos 5t\right)^2} \, dt\]
Simplify the expression inside the square root if possible, then set up the integral for evaluation. This integral may require numerical methods or further trigonometric simplifications to solve.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Parametric Equations

Parametric equations express the coordinates of points on a curve as functions of a parameter, often denoted t. Instead of y as a function of x, both x and y depend on t, allowing the description of more complex curves. Understanding how to work with parametric forms is essential for calculating properties like curve length.
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Arc Length Formula for Parametric Curves

The length of a curve defined parametrically by x(t) and y(t) from t = a to t = b is found by integrating the square root of the sum of the squares of the derivatives: ∫ₐᵇ √[(dx/dt)² + (dy/dt)²] dt. This formula generalizes the Pythagorean theorem to infinitesimal segments along the curve.
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Differentiation of Trigonometric Functions

Calculating the derivatives dx/dt and dy/dt requires knowledge of differentiating trigonometric functions like sine and cosine. Recognizing the derivatives (d/dt) sin t = cos t and (d/dt) cos t = -sin t is crucial for correctly applying the arc length formula to the given parametric equations.
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