Algebra and Trigonometry
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x=0x=0x=0
x=1x=1x=1
x=13x=\(\frac\)13x=31
No solution
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Solve the equation.
2x+4x−1=5\(\frac{2x+4}{x-1}\)=5
−5x+4−3=x−1x+4\(\frac{-5}{x+4}\)-3=\(\frac{x-1}{x+4}\)