Algebra and Trigonometry
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Solve the equation.
−5x+4−3=x−1x+4\(\frac{-5}{x+4}\)-3=\(\frac{x-1}{x+4}\)
5x−23x=4+3x\(\frac{5}{x}\)-\(\frac{2}{3x}\)=4+\(\frac{3}{x}\)
2x+4x−1=5\(\frac{2x+4}{x-1}\)=5