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Ch 35: Optical Instruments
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 35, Problem 47b

A beam of white light enters a transparent material. Wavelengths for which the index of refraction is n are refracted at angle θ₂. Wavelengths for which the index of refraction is n + δn, where δn << n, are refracted at angle θ₂ + δθ. A beam of white light is incident on a piece of glass at 30°. Deep violet light is refracted 0.28° more than deep red light. The index of refraction for deep red light is known to be 1.552. What is the index of refraction for deep violet light?

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Step 1: Begin by recalling Snell's Law, which governs the refraction of light at the interface between two media. Snell's Law is expressed as: n1sin(θ1)=n2sin(θ2), where n1 and n2 are the indices of refraction of the two media, and θ1 and θ2 are the angles of incidence and refraction, respectively.
Step 2: Recognize that the problem involves two wavelengths of light (deep red and deep violet) refracted at slightly different angles due to their differing indices of refraction. The difference in refraction angles is given as δθ = 0.28°.
Step 3: Use the small-angle approximation for refraction, which states that for small changes in the index of refraction (δn), the change in the refraction angle (δθ) can be related to δn using the derivative of Snell's Law. This gives: δθ=δnn2, where n2 is the index of refraction for deep red light.
Step 4: Substitute the known values into the equation. The index of refraction for deep red light is n2 = 1.552, and the angular difference is δθ = 0.28°. Rearrange the equation to solve for δn: δn=n2δθ.
Step 5: Add the calculated δn to the index of refraction for deep red light to find the index of refraction for deep violet light: nviolet=nred+δn.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Refraction

Refraction is the bending of light as it passes from one medium to another with a different density, which changes its speed. This phenomenon is governed by Snell's Law, which relates the angles of incidence and refraction to the indices of refraction of the two media. Understanding refraction is crucial for analyzing how different wavelengths of light behave when entering materials like glass.
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Index of Refraction

Index of Refraction

The index of refraction (n) is a dimensionless number that describes how much light slows down in a medium compared to its speed in a vacuum. It is defined as the ratio of the speed of light in vacuum to the speed of light in the medium. Different wavelengths of light have different indices of refraction, which leads to dispersion, where colors are separated based on their wavelengths.
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Index of Refraction

Dispersion

Dispersion occurs when different wavelengths of light are refracted by different amounts as they pass through a medium, resulting in a spectrum of colors. This effect is evident in prisms and is responsible for phenomena such as rainbows. In the context of the question, the difference in refraction angles for deep violet and deep red light illustrates how dispersion affects the path of light through glass.
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Related Practice
Textbook Question

FIGURE CP35.50 shows a lens combination in which the lens separation is less than the focal length of the converging lens. The procedure for combination lenses is to let the image of the first lens be the object for the second lens, but in this case the image of the first lens—shown as a dot—is on the far side of the second lens. This is called a virtual object, a point that light rays are converging toward but never reach. The top half of Figure CP35.50 shows that the converging rays are refracted again by the diverging lens and come to a focus farther to the right. The procedure for combination lenses will continue to work if we use a negative object distance for a virtual object. Equation 35.1 defined the effective focal length feff of a lens combination, but we didn't discuss how it is used. Although an actual ray refracts twice, once at each lens, we can extend the output rays leftward to where they need to bend only once in a plane called the principal plane. The principal plane is similar to the lens plane of a single lens, where a single bend occurs, but the principal plane generally does not coincide with the physical lens; it's just a mathematical plane in space. The effective focal length is measured from the principal plane, so parallel input rays are focused at distance feff beyond the principal plane. Find the positions of the principal planes for lens separations of 5 cm and 10 cm. Give your answers as distances to the left of the diverging lens.

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Textbook Question

Alpha Centauri, the nearest star to our solar system, is 4.3 light years away. Assume that Alpha Centauri has a planet with an advanced civilization. Professor Dhg, at the planet’s Astronomical Institute, wants to build a telescope with which he can find out whether any planets are orbiting our sun. Building a telescope of the necessary size does not appear to be a major problem. What practical difficulties might prevent Professor Dhg’s experiment from succeeding?

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Textbook Question

The resolution of a digital camera is limited by two factors: diffraction by the lens, a limit of any optical system, and the fact that the sensor is divided into discrete pixels. Consider a typical point-and-shoot camera that has a 20-mm-focal-length lens and a sensor with 2.5μm x 2.5 μm pixels. What is the f-number of the lens for the diameter you found in part b? Your answer is a quite realistic value of the f-number at which a camera transitions from being pixel limited to being diffraction limited. For f-numbers smaller than this (larger-diameter apertures), the resolution is limited by the pixel size and does not change as you change the aperture. For f-numbers larger than this (smaller-diameter apertures), the resolution is limited by diffraction, and it gets worse as you “stop down” to smaller apertures.

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Textbook Question

The lens shown in FIGURE CP35.49 is called an achromatic doublet, meaning that it has no chromatic aberration. The left side is flat, and all other surfaces have radii of curvature R. Because of dispersion, either lens alone would focus red rays and blue rays at different points. Define ∆n1 and ∆n2 as nblue - nred for the two lenses. What value of the ratio ∆n1 / ∆n2 makes fblue = fred for the two-lens system? That is, the two-lens system does not exhibit chromatic aberration.

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Textbook Question

The Hubble Space Telescope has a mirror diameter of 2.4 m. Suppose the telescope is used to photograph stars near the center of our galaxy, 30,000 light years away, using red light with a wavelength of 650 nm. For comparison, what is this distance as a multiple of the distance of Jupiter from the sun?

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