Textbook Question
An object is 20 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the image. Is the upright or inverted?
2
views
Ch 34: Ray Optics
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796
Not the one you use?Change textbookSelect a different textbook
Table of contents
- Ch 01: Concepts of Motion35
- Ch 02: Kinematics in One Dimension75
- Ch 03: Vectors and Coordinate Systems58
- Ch 04: Kinematics in Two Dimensions60
- Ch 05: Force and Motion23
- Ch 06: Dynamics I: Motion Along a Line53
- Ch 07: Newton's Third Law27
- Ch 08: Dynamics II: Motion in a Plane52
- Ch 09: Work and Kinetic Energy56
- Ch 10: Interactions and Potential Energy50
- Ch 11: Impulse and Momentum56
- Ch 12: Rotation of a Rigid Body71
- Ch 13: Newton's Theory of Gravity52
- Ch 14: Fluids and Elasticity44
- Ch 15: Oscillations55
- Ch 16: Traveling Waves37
- Ch 17: Superposition39
- Ch 18: A Macroscopic Description of Matter53
- Ch 19: Work, Heat, and the First Law of Thermodynamics60
- Ch 20: The Micro/Macro Connection53
- Ch 21: Heat Engines and Refrigerators34
- Ch 22: Electric Charges and Forces40
- Ch 23: The Electric Field39
- Ch 24: Gauss' Law32
- Ch 25: The Electric Potential63
- Ch 26: Potential and Field57
- Ch 27: Current and Resistance42
- Ch 28: Fundamentals of Circuits39
- Ch 29: The Magnetic Field47
- Ch 30: Electromagnetic Induction60
- Ch 31: Electromagnetic Fields and Waves32
- Ch 32: AC Circuits63
- Ch 33: Wave Optics32
- Ch 34: Ray Optics57
- Ch 35: Optical Instruments30
- Ch 36: Special Relativity38
- Ch 37: The Foundations of Modern Physics25
- Ch 38: Quantization49
- Ch 39: Wave Functions and Uncertainty31
- Ch 40: One-Dimensional Quantum Mechanics35
- Ch 41: Atomic Physics18
- Ch 42: Nuclear Physics27
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 34, Problem 19
To a fish in an aquarium, the 4.00-mm-thick walls appear to be only 3.50 mm thick. What is the index of refraction of the walls?
Verified step by step guidance1
Step 1: Understand the problem. The apparent thickness of the aquarium wall is less than its actual thickness due to refraction. This phenomenon occurs because light bends when it passes from one medium to another. The relationship between the actual thickness, apparent thickness, and the index of refraction can be expressed using the formula: , where is the index of refraction, is the actual thickness, and is the apparent thickness.
Step 2: Identify the given values. From the problem, the actual thickness of the aquarium wall is , and the apparent thickness is . These values will be substituted into the formula to calculate the index of refraction.
Step 3: Write the formula for the index of refraction. The formula is: . This equation relates the actual thickness, apparent thickness, and the index of refraction.
Step 4: Substitute the given values into the formula. Replace with and with . The equation becomes: .
Step 5: Simplify the fraction to find the index of refraction. Perform the division to calculate the value of . This will give the index of refraction of the aquarium walls.
Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Refraction
Refraction is the bending of light as it passes from one medium to another with a different density. This phenomenon occurs due to changes in the speed of light in different materials, which can cause objects to appear distorted or shifted in position. Understanding refraction is essential for analyzing how light interacts with the aquarium walls and affects the perceived thickness.
Recommended video:
Guided course
03:46
Index of Refraction
Index of Refraction
The index of refraction (n) is a dimensionless number that describes how much light slows down in a medium compared to its speed in a vacuum. It is defined as the ratio of the speed of light in a vacuum to the speed of light in the medium. The index of refraction is crucial for determining how light behaves at the interface between different materials, such as the aquarium walls and water.
Recommended video:
Guided course
03:46Index of Refraction
Apparent Thickness
Apparent thickness refers to the perceived thickness of an object when viewed through a different medium, influenced by the refraction of light. In this scenario, the fish perceives the aquarium walls as thinner than they actually are due to the bending of light at the water-wall interface. This concept is key to solving the problem, as it relates the actual thickness of the walls to the perceived thickness experienced by the fish.
Recommended video:
07:49Ray Diagrams for Convex Mirrors
Related Practice
Textbook Question
Find the focal length of the plano-concave polystyrene plastic lens in FIGURE EX34.25.
1
views
Textbook Question
An underwater diver sees the sun 50° above horizontal. How high is the sun above the horizon to a fisherman in a boat above the diver?
1
views
Textbook Question
A biologist keeps a specimen of his favorite beetle embedded in a cube of polystyrene plastic. The hapless bug appears to be 2.0 cm within the plastic. What is the beetle's actual distance beneath the surface?
1
views
Textbook Question
A giant ocean tank at an aquarium has acrylic plastic walls 18 cm thick. The index of refraction of acrylic plastic is 1.49. A fish is 220 cm from the inside wall. To a viewer on the outside, how far does the fish appear to be from the outside wall? Hint: The of the first refraction is the object for the second refraction.
1
views
Textbook Question
The glass core of an optical fiber has an index of refraction 1.60. The index of refraction of the cladding is 1.48. What is the maximum angle a light ray can make with the wall of the core if it is to remain inside the fiber?
2
views