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Ch 19: Work, Heat, and the First Law of Thermodynamics
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 19, Problem 38

A 5.0-m-diameter garden pond is 30 cm deep. Solar energy is incident on the pond at an average rate of 400 W/m2. If the water absorbs all the solar energy and does not exchange energy with its surroundings, how many hours will it take to warm from 15°C to 25°C?

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Calculate the volume of the pond. The pond is cylindrical, so its volume is given by the formula: \( V = \pi r^2 h \), where \( r \) is the radius (half the diameter) and \( h \) is the depth. Convert the depth from cm to meters before substituting.
Determine the mass of the water in the pond. Use the relationship \( m = \rho V \), where \( \rho \) is the density of water (approximately \( 1000 \ \text{kg/m}^3 \)) and \( V \) is the volume calculated in the previous step.
Calculate the energy required to raise the temperature of the water from 15°C to 25°C. Use the formula \( Q = mc\Delta T \), where \( m \) is the mass of the water, \( c \) is the specific heat capacity of water (\( 4186 \ \text{J/kg°C} \)), and \( \Delta T \) is the temperature change (\( 25 - 15 = 10 \ \text{°C} \)).
Determine the rate at which energy is absorbed by the pond. The power absorbed is given by \( P = I A \), where \( I \) is the solar energy incident rate (\( 400 \ \text{W/m}^2 \)) and \( A \) is the surface area of the pond (\( A = \pi r^2 \)).
Calculate the time required to absorb the energy \( Q \) at the rate \( P \). Use the formula \( t = \frac{Q}{P} \). Convert the time from seconds to hours by dividing by 3600.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Energy Absorption

Energy absorption refers to the process by which an object takes in energy from its surroundings. In this context, the pond absorbs solar energy at a rate of 400 W/m², which is the power per unit area received from sunlight. This energy is crucial for raising the temperature of the water in the pond.
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Specific Heat Capacity

Specific heat capacity is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius. For water, this value is approximately 4.18 J/g°C. Understanding this concept is essential for calculating how much energy is needed to increase the pond's water temperature from 15°C to 25°C.
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Heat Transfer and Time Calculation

Heat transfer involves the movement of thermal energy from one object to another, which in this case is the energy absorbed by the pond water. To determine how long it will take to warm the water, one must calculate the total energy required to achieve the desired temperature change and then relate this to the rate of energy absorption from the solar radiation.
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Related Practice
Textbook Question

A 5.0 g ice cube at −20°C is in a rigid, sealed container from which all the air has been evacuated. How much heat is required to change this ice cube into steam at 200°C? Steam has cV = 1500 J/kg K and cP = 1960 J/kg K.

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Textbook Question

The burner on an electric stove has a power output of 2.0 kW. A 750 g stainless steel teakettle is filled with 20°C water and placed on the already hot burner. If it takes 3.0 min for the water to reach a boil, what volume of water, in cm3, was in the kettle? Stainless steel is mostly iron, so you can assume its specific heat is that of iron.

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Textbook Question

You are boiling pasta and absentmindedly grab a copper stirring spoon rather than your wooden spoon. The copper spoon has a 20 mm ×1.5 mm rectangular cross section, and the distance from the boiling water to your 35°C hand is 18 cm. How long does it take the spoon to transfer 25 J of energy to your hand?

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Textbook Question

When air is inhaled, it quickly becomes saturated with water vapor as it passes through the moist airways. Consequently, an adult human exhales about 25 mg of evaporated water with each breath. Evaporation—a phase change—requires heat, and the heat energy is removed from your body. Evaporation is much like boiling, only water's heat of vaporization at 35°C is a somewhat larger 24×105 J/kg because at lower temperatures more energy is required to break the molecular bonds. At 12 breaths/min, on a dry day when the inhaled air has almost no water content, what is the body's rate of energy loss (in J/s) due to exhaled water? (For comparison, the energy loss from radiation, usually the largest loss on a cool day, is about 100 J/s.)

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Textbook Question

A gas cylinder holds 0.10 mol of O₂ at 150°C and a pressure of 3.0 atm. The gas expands adiabatically until the volume is doubled. What are the final pressure?

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Textbook Question

The ends of a 20-cm-long, 2.0-cm-diameter rod are maintained at 0°C and 100°C by immersion in an ice-water bath and boiling water. Heat is conducted through the rod at 4.5×104 J per hour. Of what material is the rod made?

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