Skip to main content
Ch 14: Fluids and Elasticity
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 14, Problem 49

The average density of the body of a fish is 1080 kg/m³ . To keep from sinking, a fish increases its volume by inflating an internal air bladder, known as a swim bladder, with air. By what percent must the fish increase its volume to be neutrally buoyant in fresh water? The density of air at 20°C is 119 kg/m³.

Verified step by step guidance
1
Determine the condition for neutral buoyancy: For the fish to be neutrally buoyant, the average density of the fish (including the swim bladder) must equal the density of fresh water, which is approximately 1000 kg/m³.
Express the average density of the fish after inflating the swim bladder: Let the initial volume of the fish be \( V \) and its mass be \( m \). The initial density is \( \rho_{\text{fish}} = \frac{m}{V} \). After inflating the swim bladder, the new volume becomes \( V' = V + \Delta V \), where \( \Delta V \) is the increase in volume. The new average density is \( \rho_{\text{new}} = \frac{m}{V + \Delta V} \).
Set the new average density equal to the density of fresh water: \( \rho_{\text{new}} = \rho_{\text{water}} \). Substituting, \( \frac{m}{V + \Delta V} = 1000 \). Rearrange to solve for \( \Delta V \): \( \Delta V = \frac{m}{1000} - V \).
Relate the mass of the fish to its initial density and volume: Since \( m = \rho_{\text{fish}} \cdot V \), substitute this into the equation for \( \Delta V \): \( \Delta V = \frac{\rho_{\text{fish}} \cdot V}{1000} - V \). Factor out \( V \): \( \Delta V = V \left( \frac{\rho_{\text{fish}}}{1000} - 1 \right) \).
Calculate the percentage increase in volume: The percentage increase is given by \( \frac{\Delta V}{V} \times 100 \). Substituting \( \Delta V \), the percentage increase is \( \left( \frac{\rho_{\text{fish}}}{1000} - 1 \right) \times 100 \). Use \( \rho_{\text{fish}} = 1080 \) kg/m³ to find the final percentage.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
8m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Buoyancy

Buoyancy is the upward force exerted by a fluid that opposes the weight of an object immersed in it. This force is determined by the volume of fluid displaced by the object, which is governed by Archimedes' principle. For an object to be neutrally buoyant, the buoyant force must equal the object's weight, allowing it to neither sink nor float.
Recommended video:
Guided course
11:06
Intro to Buoyancy & Buoyant Force

Density

Density is defined as mass per unit volume, typically expressed in kilograms per cubic meter (kg/m³). It is a crucial factor in determining whether an object will float or sink in a fluid. In this scenario, the fish's density must be adjusted to match the density of fresh water (approximately 1000 kg/m³) to achieve neutral buoyancy.
Recommended video:
Guided course
8:13
Intro to Density

Volume Increase for Neutral Buoyancy

To achieve neutral buoyancy, a fish must increase its volume so that its overall density matches that of the surrounding water. This involves inflating the swim bladder with air, which has a much lower density than water. The percentage increase in volume can be calculated by determining the required volume that results in a density equal to that of the water, considering the fish's original density.
Recommended video:
Guided course
05:21
Volume Thermal Expansion
Related Practice
Textbook Question

An aquarium of length L, width (front to back) W, and depth D is filled to the top with liquid of density ρ. Find an expression for the force of the liquid on the front window of the aquarium.

1
views
Textbook Question

Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm until the height of the alcohol column is 20 cm. The two liquids do not mix. What is the difference in height between the top surface of the glycerin and the top surface of the alcohol?

2
views
Textbook Question

One day when you come into physics lab you find several plastic hemispheres floating like boats in a tank of fresh water. Each lab group is challenged to determine the heaviest rock that can be placed in the bottom of a plastic boat without sinking it. You get one try. Sinking the boat gets you no points, and the maximum number of points goes to the group that can place the heaviest rock without sinking. You begin by measuring one of the hemispheres, finding that it has a mass of 21 g and a diameter of 8.0 cm. What is the mass of the heaviest rock that, in perfectly still water, won't sink the plastic boat?

1
views
Textbook Question

It's possible to use the ideal-gas law to show that the density of the earth's atmosphere decreases exponentially with height. That is, ρ = ρ₀ exp (-z/z₀), where z is the height above sea level, ρ₀ is the density at sea level (you can use the Table 14.1 value), and z₀ is called the scale height of the atmosphere. What is the density of the air in Denver, at an elevation of 1600 m? What percent of sea-level density is this?

2
views
Textbook Question

A nonviscous liquid of density p flows at speed v₀ through a horizontal pipe that expands smoothly from diameter d₀ to a larger diameter d₁. The pressure in the narrower section is p₀. Find an expression for the pressure p₁ in the wider section.

2
views
Textbook Question

A nuclear power plant draws 3.0 x 106 L/min of cooling water from the ocean. If the water is drawn in through two parallel, 3.0-m-diameter pipes, what is the water speed in each pipe?

1
views