A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1000 N, the players have equal pulls, and the angle between the two ropes is 20°. How hard must each player pull to drag the coach at a steady 2.0 m/s?
Ch 06: Dynamics I: Motion Along a Line
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 6, Problem 6a
In an electricity experiment, a 1.0 g plastic ball is suspended on a 60-cm-long string and given an electric charge. A charged rod brought near the ball exerts a horizontal electrical force Felectric on it, causing the ball to swing out to a 20° angle and remain there. What is the magnitude of Felectric?
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Step 1: Begin by analyzing the forces acting on the ball. The ball is in equilibrium, meaning the net force is zero. The forces acting on the ball are: (1) the tension in the string, (2) the gravitational force (F_gravity), and (3) the horizontal electrical force (F_electric).
Step 2: Break the tension force into its components. The tension force has two components: a vertical component (T_vertical) that balances the gravitational force, and a horizontal component (T_horizontal) that balances the electrical force. Use trigonometry to express these components: T_vertical = T * cos(θ) and T_horizontal = T * sin(θ), where θ = 20°.
Step 3: Relate the vertical component of the tension to the gravitational force. Since the ball is in equilibrium vertically, T_vertical = F_gravity. The gravitational force is given by F_gravity = m * g, where m = 1.0 g = 0.001 kg and g = 9.8 m/s².
Step 4: Use the relationship between T_horizontal and F_electric. Since the ball is in equilibrium horizontally, T_horizontal = F_electric. Substitute T_horizontal = T * sin(θ) into this equation.
Step 5: Combine the equations to solve for F_electric. First, find T using T_vertical = F_gravity = T * cos(θ). Then substitute T into T_horizontal = T * sin(θ) to find F_electric. The final expression for F_electric is F_electric = (m * g * sin(θ)) / cos(θ).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Electric Force
The electric force is the interaction between charged objects, described by Coulomb's law. It states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this scenario, the charged rod exerts a horizontal electric force on the plastic ball, causing it to swing to a specific angle.
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Equilibrium of Forces
In this experiment, the ball is in equilibrium, meaning the net force acting on it is zero. The forces acting on the ball include the gravitational force pulling it downward and the electric force acting horizontally. The tension in the string provides a vertical component that balances the weight of the ball and a horizontal component that balances the electric force, allowing the ball to remain at a constant angle.
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Equilibrium
Trigonometric Functions
Trigonometric functions, such as sine and cosine, are essential for analyzing the forces acting on the ball at the 20-degree angle. By resolving the tension in the string into its vertical and horizontal components, we can use these functions to relate the angle to the forces. This allows us to calculate the magnitude of the electric force by setting the horizontal component of tension equal to the electric force.
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Related Practice
Textbook Question
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Textbook Question
A horizontal rope is tied to a 50 kg box on frictionless ice. What is the tension in the rope if: The box moves at a steady 5.0 m/s?
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Textbook Question
FIGURE EX6.10 shows the force acting on a 2.0 kg object as it moves along the x-axis. The object is at rest at the origin at t = 0 s. What are its acceleration and velocity at t = 6 s?
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The forces in FIGURE EX6.9 act on a 2.0 kg object. What are the values of ax and ay, the x- and y-components of the object's acceleration?
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The three ropes in FIGURE EX6.1 are tied to a small, very light ring. Two of these ropes are anchored to walls at right angles with the tensions shown in the figure. What are the magnitude and direction of the tension T3 in the third rope?
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