Textbook Question
Complete the following proposed acid–base reactions, and predict whether the reactants or products are favored.
(a)
(b)
1
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Ch. 19 - Amines
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 19, Problem 38a
Predict the products of the following reactions:
(a) excess NH3 + Ph–CH2CH2CH2Br →
Verified step by step guidance1
Step 1: Recognize the type of reaction. This is a nucleophilic substitution reaction where ammonia (NH₃) acts as the nucleophile and the alkyl bromide (Ph-CH₂CH₂CH₂Br) is the electrophile.
Step 2: Identify the mechanism. Since the alkyl bromide is a primary alkyl halide, the reaction will likely proceed via an SN2 mechanism, where the nucleophile attacks the carbon attached to the bromine, displacing the bromine atom.
Step 3: Write the first substitution step. Ammonia (NH₃) will attack the carbon bonded to the bromine, forming a new bond between the carbon and the nitrogen. This results in the formation of a primary amine (Ph-CH₂CH₂CH₂-NH₂) and the release of bromide ion (Br⁻).
Step 4: Consider the effect of excess NH₃. Since excess ammonia is present, the primary amine product can further react with another molecule of alkyl bromide, leading to the formation of a secondary amine (Ph-CH₂CH₂CH₂-NH-CH₂CH₂CH₂Ph) and so on. This process can continue to form tertiary amines or even quaternary ammonium salts.
Step 5: Summarize the possible products. Depending on the reaction conditions and the amount of excess NH₃, the products can include a primary amine, secondary amine, tertiary amine, or quaternary ammonium salt. The reaction can be controlled to favor specific products by adjusting the stoichiometry and reaction conditions.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Nucleophilic Substitution
Nucleophilic substitution is a fundamental reaction in organic chemistry where a nucleophile attacks an electrophile, resulting in the replacement of a leaving group. In this case, the bromine atom in Ph-CH2CH2CH2Br acts as the leaving group, while ammonia (NH3) serves as the nucleophile. Understanding this mechanism is crucial for predicting the products of the reaction.
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Nucleophiles and Electrophiles can react in Substitution Reactions.
Amine Formation
The reaction of ammonia with alkyl halides typically leads to the formation of amines. In this scenario, the nucleophilic attack by NH3 on the carbon attached to the bromine results in the formation of a primary amine. Recognizing the type of amine produced is essential for accurately predicting the final products of the reaction.
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Excess Reagent Effects
Using an excess of a reagent, such as ammonia in this reaction, can influence the outcome by driving the reaction to completion and potentially leading to further reactions. In this case, excess NH3 can lead to the formation of multiple amine products, including secondary and tertiary amines, if the reaction conditions allow for further substitution. Understanding the implications of using excess reagents is vital for predicting all possible products.
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Related Practice
Textbook Question
Predict the products of the following reactions:
(c)
(d)
1
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Textbook Question
Predict the products of the following reactions:
(e)
(f)
2
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Textbook Question
Which of the following compounds are capable of being resolved into enantiomers?
(d) 1,2,2-trimethylaziridine
(e)
(f)
1
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Textbook Question
Predict the products of the following reactions:
(g)
2
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Textbook Question
Which of the following compounds are capable of being resolved into enantiomers?
(g)
(h)
2
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