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Multiple Choice
Compound 1 has two chiral centers and no plane of symmetry. How many stereoisomers of compound 1 exist?
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1
Identify the number of chiral centers in the compound. Here, compound 1 has 2 chiral centers.
Recall the general formula for the maximum number of stereoisomers for a molecule with n chiral centers: \$2^{n}$.
Apply the formula with \(n = 2\): \$2^{2} = 4$ possible stereoisomers.
Consider if there is any plane of symmetry or meso forms that could reduce the number of stereoisomers. Since the problem states there is no plane of symmetry, no meso forms exist.
Conclude that the total number of stereoisomers for compound 1 is 4.