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Multiple Choice
Given a molecule with three chiral centers and no internal plane of symmetry, what is the maximum number of stereoisomers possible for this molecule ( where is the number of chiral centers)?
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1
Identify the number of chiral centers in the molecule, which is given as \(n = 3\).
Recall the formula for the maximum number of stereoisomers possible for a molecule with \(n\) chiral centers: \$2^{n}$.
Substitute the value of \(n\) into the formula: \$2^{3}$.
Calculate the expression \$2^{3}$, which represents the total number of stereoisomers without any internal symmetry considerations.
Since the molecule has no internal plane of symmetry, all stereoisomers are unique, so the maximum number of stereoisomers is \$8$.