Skip to main content
Ch. 4 - Inverse, Exponential, and Logarithmic Functions
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 5, Problem 100

Work each problem. Which of the following is equivalent to ln(4x) - ln(2x) for x > 0? A. 2 ln x B. ln 2x C. (ln 4x)/(ln 2x) D. ln 2

Verified step by step guidance
1
Recall the logarithmic property that states: \(\ln a - \ln b = \ln \left( \frac{a}{b} \right)\) for positive values of \(a\) and \(b\).
Apply this property to the expression \(\ln(4x) - \ln(2x)\) by writing it as \(\ln \left( \frac{4x}{2x} \right)\).
Simplify the fraction inside the logarithm: \(\frac{4x}{2x} = 2\) since \(x > 0\) and cancels out.
Rewrite the expression as \(\ln(2)\) after simplification.
Compare the simplified expression \(\ln(2)\) with the given options to identify the equivalent expression.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
1m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Properties of Logarithms

Logarithms have specific properties that simplify expressions, such as the difference rule: ln(a) - ln(b) = ln(a/b). This property allows combining or breaking down logarithmic expressions by converting subtraction into division inside a single logarithm.
Recommended video:
5:36
Change of Base Property

Domain Restrictions for Logarithmic Functions

The argument of a logarithm must be positive, so for ln(4x) and ln(2x), x must be greater than zero. Understanding domain restrictions ensures the expression is valid and helps avoid undefined values during simplification.
Recommended video:
3:51
Domain Restrictions of Composed Functions

Simplifying Algebraic Expressions Inside Logarithms

When simplifying ln(4x) - ln(2x), use algebraic manipulation inside the logarithm: (4x)/(2x) simplifies to 2, since x > 0. Recognizing how to simplify fractions inside logarithms is key to finding the equivalent expression.
Recommended video:
Guided course
05:07
Simplifying Algebraic Expressions