8. Conic Sections

Find the focus and directrix of the parabola with the given equation. Then graph the parabola. y² - 6x = 0

Identify the conic represented by the equation without completing the square. 4x^2 - 9y^2 - 8x + 12y - 144 = 0

Find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 3)² = 12(x + 1)

Find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)

In Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x

In Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations.

$\{\begin{array}{c}{(y-2)}^2=x+4\\ y=-\text{(}\frac{1}{2}\text{)}x\end{array}$

Graph the parabola $-4\(\left\)(y+1\(\right\))=\(\left\)(x+1\(\right\))^2$, and find the focus point and directrix line.

Find the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)