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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.5.27

Use l’Hôpital’s rule to find the limits in Exercises 7–52.
27. lim (x → (π/2)^-) (x - π/2) sec x

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Identify the limit expression: \(\lim_{x \to (\pi/2)^-} (x - \pi/2) \sec x\).
Check the form of the limit by substituting \(x = \pi/2\) from the left side: \((x - \pi/2)\) approaches 0, and \(\sec x = \frac{1}{\cos x}\) tends to \(\pm \infty\) because \(\cos(\pi/2) = 0\). This suggests an indeterminate form of type \(0 \cdot \infty\).
Rewrite the expression to apply l’Hôpital’s rule by converting the product into a quotient. For example, write it as \(\frac{x - \pi/2}{\cos x}\) because \(\sec x = \frac{1}{\cos x}\).
Now the limit becomes \(\lim_{x \to (\pi/2)^-} \frac{x - \pi/2}{\cos x}\), which is of the form \(\frac{0}{0}\), suitable for l’Hôpital’s rule.
Apply l’Hôpital’s rule by differentiating numerator and denominator separately: differentiate numerator \(\frac{d}{dx}(x - \pi/2) = 1\), and denominator \(\frac{d}{dx}(\cos x) = -\sin x\). Then evaluate the new limit \(\lim_{x \to (\pi/2)^-} \frac{1}{-\sin x}\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Limits and One-Sided Limits

A limit describes the value a function approaches as the input approaches a certain point. One-sided limits consider the approach from only one side, such as from the left (denoted by the minus sign). Understanding how to evaluate these limits is essential for analyzing behavior near points where the function may be undefined.
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