Skip to main content
Ch. 6 - Applications of Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 6, Problem 6.4.46

45–48. Shell and washer methods about other lines Use both the shell method and the washer method to find the volume of the solid that is generated when the region in the first quadrant bounded by y = x²,y=1, and x=0 is revolved about the following lines. 


x = -1

Verified step by step guidance
1
First, identify the region bounded by the curves: \(y = x^{2}\), \(y = 1\), and \(x = 0\) in the first quadrant. This region lies between \(x=0\) and \(x=1\) because when \(y=1\), \(x = \sqrt{1} = 1\).
For the shell method about the line \(x = -1\), consider vertical slices parallel to the axis of rotation. The radius of a shell at position \(x\) is the distance from \(x\) to \(-1\), which is \(r = x - (-1) = x + 1\). The height of the shell is the vertical distance between \(y=1\) and \(y=x^{2}\), so \(h = 1 - x^{2}\).
Set up the shell method integral for the volume \(V\) as: \(V = 2\pi \int_{0}^{1} (\text{radius})(\text{height}) \, dx = 2\pi \int_{0}^{1} (x + 1)(1 - x^{2}) \, dx\).
For the washer method about the line \(x = -1\), consider horizontal slices perpendicular to the axis of rotation. Express \(x\) in terms of \(y\): from \(y = x^{2}\), we get \(x = \sqrt{y}\). The region extends from \(y=0\) to \(y=1\).
The outer radius \(R\) is the distance from \(x = -1\) to the right boundary \(x=1\), so \(R = 1 - (-1) = 2\). The inner radius \(r\) is the distance from \(x = -1\) to the curve \(x = \sqrt{y}\), so \(r = \sqrt{y} - (-1) = \sqrt{y} + 1\). Set up the washer method integral for the volume \(V\) as: \(V = \pi \int_{0}^{1} \left(R^{2} - r^{2}\right) dy = \pi \int_{0}^{1} \left(2^{2} - (\sqrt{y} + 1)^{2}\right) dy\).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
7m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Shell Method for Volume

The shell method calculates the volume of a solid of revolution by integrating cylindrical shells. Each shell's volume is found by multiplying its circumference, height, and thickness. This method is especially useful when the axis of rotation is parallel to the axis of the function being integrated.
Recommended video:
04:48
Finding Volume Using Disks

Washer Method for Volume

The washer method involves slicing the solid perpendicular to the axis of rotation, creating washers (disks with holes). The volume is found by integrating the difference between the outer and inner radii squared, times π, over the interval. This method is ideal when the solid has a hollow center.
Recommended video:
04:48
Finding Volume Using Disks

Adjusting for Axis of Rotation Not on Coordinate Axes

When revolving around lines other than the coordinate axes, such as x = -1, distances (radii) must be measured relative to that line. This requires shifting the radius expressions by the distance from the curve to the axis of rotation, ensuring accurate calculation of shell heights or washer radii.
Recommended video:
3:00
Determining Different Coordinates for the Same Point Example 2