Ch. 5 - Integration

Briggs - Calculus: Early Transcendentals 3rd Edition

Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook

Briggs 3rd Edition

Ch. 5 - Integration

Problem 5.3.23

Chapter 5, Problem 5.3.23

Definite integrals Evaluate the following integrals using the Fundamental Theorem of Calculus. Explain why your result is consistent with the figure.

∫₀¹ (𝓍² ― 2𝓍 + 3) d𝓍

Verified step by step guidance

Step 1: Recognize that the problem involves evaluating the definite integral ∫₀¹ (𝓍² - 2𝓍 + 3) d𝓍 using the Fundamental Theorem of Calculus. The integral represents the area under the curve y = 𝓍² - 2𝓍 + 3 from x = 0 to x = 1.

Step 2: Find the antiderivative of the integrand (𝓍² - 2𝓍 + 3). The antiderivative is calculated term by term: ∫𝓍² d𝓍 = (𝓍³/3), ∫(-2𝓍) d𝓍 = -𝓍², and ∫3 d𝓍 = 3𝓍. Combine these to get the antiderivative F(𝓍) = (𝓍³/3) - 𝓍² + 3𝓍.

Step 3: Apply the Fundamental Theorem of Calculus, which states that the definite integral ∫ₐᵇ f(𝓍) d𝓍 = F(b) - F(a), where F(𝓍) is the antiderivative of f(𝓍). Here, evaluate F(1) and F(0).

Step 4: Substitute x = 1 into the antiderivative F(𝓍) to find F(1). Then substitute x = 0 into F(𝓍) to find F(0). Compute the difference F(1) - F(0) to determine the value of the definite integral.

Step 5: Verify that the result is consistent with the figure. The graph shows the curve y = 𝓍² - 2𝓍 + 3, and the shaded region represents the area under the curve from x = 0 to x = 1. The definite integral calculates this exact area, confirming the consistency between the result and the figure.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Definite Integrals

A definite integral represents the signed area under a curve between two specified limits on the x-axis. It is calculated using the integral symbol and provides a numerical value that corresponds to the total accumulation of the function's values over that interval. In this case, the integral ∫₀¹ (𝓍² - 2𝓍 + 3) d𝓍 calculates the area under the curve from x = 0 to x = 1.

Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus links the concept of differentiation with integration, stating that if a function is continuous on an interval, then the integral of its derivative over that interval equals the difference in the values of the original function at the endpoints. This theorem allows us to evaluate definite integrals by finding an antiderivative of the integrand and applying the limits of integration.

Graphical Interpretation of Integrals

The graphical interpretation of integrals involves visualizing the area under a curve as the integral's value. In the provided figure, the shaded region represents the area under the curve of the function y = x² - 2x + 3 from x = 0 to x = 1. This area corresponds to the result of the definite integral, illustrating how the integral quantifies the accumulation of the function's values over the specified interval.

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Definite integrals Evaluate the following integrals using the Fundamental Theorem of Calculus. Explain why your result is consistent with the figure.∫₀¹ (𝓍² ― 2𝓍 + 3) d𝓍

Verified video answer for a similar problem:

Key Concepts

Definite Integrals

Fundamental Theorem of Calculus

Graphical Interpretation of Integrals

Definite integrals Evaluate the following integrals using the Fundamental Theorem of Calculus. Explain why your result is consistent with the figure.

∫₀¹ (𝓍² ― 2𝓍 + 3) d𝓍