Skip to main content
Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 2, Problem 17

Suppose p and q are polynomials. If lim x→0 p(x) / q(x)=10 and q(0)=2, find p(0).

Verified step by step guidance
1
Identify the given limit: \( \lim_{x \to 0} \frac{p(x)}{q(x)} = 10 \).
Recognize that \( q(0) = 2 \) is given, which means \( q(x) \) is not zero at \( x = 0 \).
Apply the limit definition: \( \lim_{x \to 0} \frac{p(x)}{q(x)} = \frac{p(0)}{q(0)} \).
Substitute the known values into the limit equation: \( \frac{p(0)}{2} = 10 \).
Solve for \( p(0) \) by multiplying both sides by 2.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
2m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Limits

In calculus, a limit describes the behavior of a function as its input approaches a certain value. The notation lim x→0 p(x) / q(x) indicates the limit of the ratio of two polynomials p(x) and q(x) as x approaches 0. Understanding limits is crucial for evaluating expressions that may be indeterminate at specific points.
Recommended video:
05:50
One-Sided Limits

Polynomial Functions

Polynomials are mathematical expressions consisting of variables raised to non-negative integer powers and their coefficients. They can be represented in the form p(x) = a_n x^n + a_(n-1) x^(n-1) + ... + a_1 x + a_0. The behavior of polynomials near specific points, such as x=0, is essential for evaluating limits and understanding continuity.
Recommended video:
6:04
Introduction to Polynomial Functions

Continuity and Evaluation at a Point

A function is continuous at a point if the limit of the function as it approaches that point equals the function's value at that point. In this case, since lim x→0 p(x) / q(x) = 10 and q(0) = 2, we can use the limit to find p(0) by rearranging the limit expression, leading to p(0) = 10 * q(0).
Recommended video:
05:34
Intro to Continuity