y-tan3x-is-horizontally-shifted-right-by-6-what-is-the-period-of-the-original-ta

Question

y = tan((π/3)x) is horizontally shifted right by π/6. What is the period of the original tan((π/3)x), and how much horizontally do the vertical asymptotes move under the shift? (Describe the original period and the translation of asymptote positions.)

Accepted Answer

Period = 3; asymptotes shift right by π/6 from x = 1.5(2k+1) to x = 1.5(2k+1) + π/6

Answer

Period = 9/2 and asymptotes shift right by 3π/2

Answer

Period = 3

Answer

Period = π/3 and asymptotes shift left by π/6