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Question

Find the value of cos⁡5π12\cos\frac{5\pi}{12} as cos⁡(π6+π4)\cos\left(\frac{\pi}{6}+\frac{\pi}{4}\right).

Accepted Answer

cos⁡(5π12)=6−24\cos\left(\frac{5\pi}{12}\right)=\frac{\sqrt{6} - \sqrt{2}}{4}

Answer

cos⁡(5π12)=6+22\cos\left(\frac{5\pi}{12}\right)=\frac{\sqrt{6}+\sqrt{2}}{2}

Answer

cos⁡(5π12)=6−22\cos\left(\frac{5\pi}{12}\right)=\frac{\sqrt{6}-\sqrt{2}}{2}

Answer

cos⁡(5π12)=6+24\cos\left(\frac{5\pi}{12}\right)=\frac{\sqrt{6}+\sqrt{2}}{4}

Find the value of cos5π12\(\cos\]\frac{5\pi}{12}\) as cos(π6+π4)\(\cos\[\left\)(\(\frac{\pi}{6}\)+\(\frac{\pi}{4}\]\right\)).