solve-2x-42-18-0-for-x-intercepts-of-the-parabola-provide-exact-values

Question

Solve 2(x−4)2−18=$$02(x-4)^2-18=0 to $$find the xx-intercepts of the parabola.

Accepted Answer

x=1x=1 or x=7x=7

Answer

x=−1x=-1 or x=−7x=-7

Answer

x=4x=4 or x=9x=9

Answer

x=2x=2 or x=18x=18

Solve 2(x−4)2−18=02(x-4)^2-18=0 to find the xx-intercepts of the parabola.