e-how-the-time-of-maximum-height-and-the-maximum-height-change-show-calculations

Question

A toy rocket's vertical position, in units of meters, is modeled by: h(t)=−5t2+20t+1h\left(t\right)=$$-5t^2+20t+1$$, where tt is in seconds. If aerodynamic drag doubles the magnitude of the $$t2t^2$$ coefficient, such that the model becomes:h2(t)=−10t2+20t+1h_2\left(t\right)=$$-10t^2+20t+1$$, determine how the time where the rocket will reach its maximum height and how the maximum height itself will change as a result.

Accepted Answer

Peak time decreases to 1 second and the max height decreases to 11 meters.

Answer

Peak time increases to 4 seconds and the max height increases to 41 meters.

Answer

Peak time remains 2 seconds, but the max height decreases to 11 meters.

Answer

Peak time decreases to 1 second, but the max height remains at 21 meters.