Evaluate the given logarithm.
${\log }_7{7}^{0.3}$

Change the following logarithmic expression to its equivalent exponential form.

${\log }_{4}x=5$.

Change the following logarithmic expression to its equivalent exponential form.

$x=\log 9$

Change the following exponential expression to its equivalent logarithmic form.

$3^x=7$

Change the following exponential expression to its equivalent logarithmic form.

$e^9=x+3$

Evaluate the given logarithm.

$\frac{3}{2}\log 1$

Evaluate the given logarithm.

${\log }_9\frac{1}{81}$