Solve the given quadratic equation using the square root property.
${(x-\frac{1}{2})}^2-5=0$

$x=\(\frac\)12+\(\sqrt\)5,x=\(\frac\)12-\(\sqrt\)5$

$x=\(\frac\)52,x=-\(\frac\)52$

$x=\(\frac{\sqrt5}{2}\),x=-\(\frac{\sqrt5}{2}\)$

$x=\(\frac\)12,x=-\(\frac\)12$