In Exercises 37–52, perform the indicated operations and write the result in standard form. ___ ___ 5√−16 + 3√−81
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
- OLD 1. Angles and the Trigonometric Functions Coming soon
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- OLD 3. Trigonometric Identities and Equations Coming soon
- OLD 4. Laws of Sines, Cosines and Vectors Coming soon
- OLD 5. Complex Numbers, Polar Coordinates and Parametric Equations Coming soon
- NEW (not used) 7. Laws of Sines, Cosines and Vectors Coming soon
- NEW (not used) 8. Vectors Coming soon
- NEW(not used) 9. Polar equations Coming soon
- NEW (not used) 11. Graphing Complex Numbers Coming soon
0. Review of College Algebra
Complex Numbers
Problem 45
Textbook Question
In Exercises 37–52, perform the indicated operations and write the result in standard form. ___ −8 + √−32 / 24
Verified step by step guidance1
Identify the expression to simplify: \(-8 + \frac{\sqrt{-32}}{24}\). Notice that the square root involves a negative number, which means we will use imaginary numbers.
Rewrite the square root of the negative number using the imaginary unit \(i\), where \(i = \sqrt{-1}\). So, \(\sqrt{-32} = \sqrt{32} \times \sqrt{-1} = \sqrt{32}i\).
Simplify \(\sqrt{32}\) by expressing it as \(\sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}\). Therefore, \(\sqrt{-32} = 4\sqrt{2}i\).
Substitute back into the expression: \(-8 + \frac{4\sqrt{2}i}{24}\). Simplify the fraction \(\frac{4\sqrt{2}i}{24}\) by dividing numerator and denominator by 4, resulting in \(\frac{\sqrt{2}i}{6}\).
Write the expression in standard form \(a + bi\), where \(a\) and \(b\) are real numbers. Here, \(a = -8\) and \(b = \frac{\sqrt{2}}{6}\). So the expression is \(-8 + \frac{\sqrt{2}}{6}i\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Complex Numbers and Imaginary Unit
Complex numbers consist of a real part and an imaginary part, expressed as a + bi, where i is the imaginary unit with the property i² = -1. Understanding how to represent and manipulate these numbers is essential when dealing with square roots of negative numbers.
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Introduction to Complex Numbers
Simplifying Square Roots of Negative Numbers
To simplify the square root of a negative number, factor out the imaginary unit i by rewriting √(-a) as i√a, where a is positive. This allows the expression to be converted into a form involving real numbers and i, facilitating further operations.
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Imaginary Roots with the Square Root Property
Operations with Complex Numbers in Standard Form
Standard form for complex numbers is a + bi, where a and b are real numbers. Performing addition, subtraction, multiplication, or division requires combining like terms and applying algebraic rules, including i² = -1, to simplify the expression correctly.
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Complex Numbers In Polar Form
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