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Ch. 9 - Inferences from Two Samples
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 9, Problem 9.R.3

Forecast and Actual Temperatures Listed below are actual temperatures (°F) along with the temperatures that were forecast five days earlier (data collected by the author). Use a 0.05 significance level to test the claim that differences between actual temperatures and temperatures forecast five days earlier are from a population with a mean of 0°F.

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State the null hypothesis (H₀) and the alternative hypothesis (H₁): H₀: μ_d = 0 (the mean difference between actual and forecast temperatures is 0°F), H₁: μ_d ≠ 0 (the mean difference is not 0°F).
Calculate the differences (d) between the actual temperatures and the forecast temperatures for each data pair. Then, compute the mean of these differences (d̄) and the standard deviation of the differences (s_d).
Determine the test statistic using the formula: t = (d̄ - μ_d) / (s_d / √n), where μ_d is the hypothesized mean difference (0°F), n is the number of data pairs, and s_d is the standard deviation of the differences.
Find the critical t-value(s) for a two-tailed test at the 0.05 significance level using the degrees of freedom (df = n - 1). Compare the calculated t-value to the critical t-value(s).
Make a decision: If the calculated t-value falls within the critical region (beyond the critical t-values), reject the null hypothesis. Otherwise, fail to reject the null hypothesis. Interpret the result in the context of the problem.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hypothesis Testing

Hypothesis testing is a statistical method used to make decisions about a population based on sample data. It involves formulating a null hypothesis (H0) and an alternative hypothesis (H1). In this context, the null hypothesis states that the mean difference between actual and forecast temperatures is 0°F, while the alternative suggests it is not. The process includes calculating a test statistic and comparing it to a critical value to determine if the null hypothesis can be rejected.
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Step 1: Write Hypotheses

Significance Level

The significance level, denoted as alpha (α), is the threshold for determining whether to reject the null hypothesis. A common significance level is 0.05, which indicates a 5% risk of concluding that a difference exists when there is none. In this scenario, using a 0.05 significance level means that if the p-value obtained from the test is less than 0.05, the null hypothesis can be rejected, suggesting that the differences in temperatures are statistically significant.
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Step 4: State Conclusion Example 4

Mean Difference

The mean difference refers to the average of the differences between paired observations—in this case, the actual temperatures and the forecasted temperatures. Calculating the mean difference helps to assess whether the forecast is accurate. If the mean difference is significantly different from 0°F, it indicates that the forecasts are systematically off, which is the primary claim being tested in this analysis.
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Difference in Means: Confidence Intervals
Related Practice
Textbook Question

F Test Statistic


a. If s2,1 represents the larger of two sample variances, can the F test statistic ever be less than 1?


Textbook Question

Smoking Cessation Programs


a. Construct the confidence interval that could be used to test the claim in Exercise 5. What feature of the confidence interval leads to the same conclusion from Exercise 5?

Textbook Question

Body Temperatures Listed below are body temperatures from six different subjects measured at two different times in a day (from Data Set 5 “Body Temperatures” in Appendix B).


b. Identify the null and alternative hypotheses for using the sample data to test the claim that the differences between 8 AM temperatures and 12 AM temperatures are from a population with a mean equal to 0°F

Textbook Question

In Exercises 5–16, use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal.


The Freshman 15 The “Freshman 15” refers to the belief that college students gain 15 lb (or 6.8 kg) during their freshman year. Listed below are weights (kg) of randomly selected male college freshmen (from Data Set 13 “Freshman 15” in Appendix B). The weights were measured in September and later in April.


a. Use a 0.01 significance level to test the claim that for the population of freshman male college students, the weights in September are less than the weights in the following April.

Textbook Question

Variation of Hospital Times Use the sample data given in Exercise 7 “Seat Belts” and test the claim that for children hospitalized after motor vehicle crashes, the numbers of days in intensive care units for those wearing seat belts and for those not wearing seat belts have the same variation. Use a 0.05 significance level.

Textbook Question

Smoking Cessation Programs Among 198 smokers who underwent a “sustained care” program, 51 were no longer smoking after six months. Among 199 smokers who underwent a “standard care” program, 30 were no longer smoking after six months (based on data from “Sustained Care Intervention and Postdischarge Smoking Cessation Among Hospitalized Adults,” by Rigotti et al., Journal of the American Medical Association, Vol. 312, No. 7). We want to use a 0.01 significance level to test the claim that the rate of success for smoking cessation is greater with the sustained care program. Test the claim using a hypothesis test.