for-the-function-fx-x2-16x-4-find-the-x-value-where-the-function-is-discontinuou

Question

For the function f(x) = $$(x^2 - 16)/(x - 4$$), find the x-value where the function is discontinuous.

Accepted Answer

x = 4

Answer

x = 0

Answer

x = 16

Answer

x = -4

For the function f(x) = (x^2 - 16)/(x - 4), find the x-value where the function is discontinuous.