In the circuit shown in Fig. E26.34, the 6.0 Ω resistor is consuming energy at a rate of 24 J/s when the current through it flows as shown. What are the polarity and emf ε of the unknown battery, assuming it has negligible internal resistance?
Ch 26: Direct-Current Circuits
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Not the one you use?Change textbook
Chapter 26, Problem 51
A 1500 W electric heater is plugged into the outlet of a 120 V circuit that has a 20 A circuit breaker. You plug an electric hair dryer into the same outlet. The hair dryer has power settings of 600 W, 900 W, 1200 W, and 1500 W. You start with the hair dryer on the 600 W setting and increase the power setting until the circuit breaker trips. What power setting caused the breaker to trip?
Verified step by step guidance1
First, calculate the current drawn by the electric heater using the formula for power: \( P = IV \), where \( P \) is power, \( I \) is current, and \( V \) is voltage. Rearrange the formula to solve for current: \( I = \frac{P}{V} \). Substitute \( P = 1500 \) W and \( V = 120 \) V to find the current drawn by the heater.
Next, determine the maximum allowable current for the circuit before the breaker trips, which is given as 20 A.
Calculate the remaining current capacity available for the hair dryer by subtracting the current drawn by the heater from the maximum allowable current: \( I_{remaining} = 20 \text{ A} - I_{heater} \).
For each power setting of the hair dryer (600 W, 900 W, 1200 W, and 1500 W), calculate the current drawn using the formula \( I = \frac{P}{V} \), where \( V = 120 \) V. Compare each calculated current with the remaining current capacity.
Identify the power setting at which the sum of the currents drawn by the heater and the hair dryer exceeds 20 A, causing the circuit breaker to trip.

Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
3mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Ohm's Law
Ohm's Law is a fundamental principle in physics that relates voltage (V), current (I), and resistance (R) in an electrical circuit through the equation V = IR. This law helps determine the current flowing through a circuit when the voltage and resistance are known, which is crucial for understanding how much current the heater and hair dryer draw from the circuit.
Recommended video:
Guided course
Resistance and Ohm's Law
Power in Electrical Circuits
Power in electrical circuits is calculated using the formula P = VI, where P is power in watts, V is voltage in volts, and I is current in amperes. This concept is essential for determining how much power each device (heater and hair dryer) consumes and how it affects the total current drawn from the circuit, which is critical for assessing when the circuit breaker will trip.
Recommended video:
Guided course
Power in Circuits
Circuit Breaker Functionality
A circuit breaker is a safety device designed to protect an electrical circuit from damage caused by excess current. It automatically interrupts the current flow when it exceeds a predetermined limit, in this case, 20 A. Understanding how a circuit breaker operates is key to determining the power setting at which the combined current from the heater and hair dryer exceeds this limit, causing the breaker to trip.
Recommended video:
Guided course
Intro to Wave Functions
Related Practice
Textbook Question
Textbook Question
The heating element of an electric dryer is rated at 4.1 kW when connected to a 240 V line. What is the resistance of the dryer's heating element at its operating temperature?
1
views
Textbook Question
An emf source with ε = 120V, a resistor with R = 80.0Ω, and a capacitor with C = 4.00 μF are connected in series. As the capacitor charges, when the current in the resistor is 0.900 A, what is the magnitude of the charge on each plate of the capacitor?
1
views
Textbook Question
In the circuit shown in Fig. E26.33 all meters are idealized and the batteries have no appreciable internal resistance. Find the reading of the voltmeter with the switch S open. Which point is at a higher potential: a or b?
