Skip to main content
Ch 28: Fundamentals of Circuits
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 28, Problem 51a

Load resistor R is attached to a battery of emf and internal resistance r. For what value of the resistance R, in terms of ∈ and r, will the power dissipated by the load resistor be a maximum?

Verified step by step guidance
1
Step 1: Start by recalling the formula for power dissipated in a resistor. The power dissipated by the load resistor R is given by \( P = I^2 R \), where \( I \) is the current through the circuit.
Step 2: Use Ohm's Law to express the current \( I \) in terms of the emf \( \varepsilon \), the internal resistance \( r \), and the load resistance \( R \). The total resistance in the circuit is \( R + r \), so \( I = \frac{\varepsilon}{R + r} \). Substitute this expression for \( I \) into the power formula.
Step 3: Substitute \( I = \frac{\varepsilon}{R + r} \) into \( P = I^2 R \). This gives \( P = \frac{\varepsilon^2 R}{(R + r)^2} \). This is the expression for power dissipated in the load resistor.
Step 4: To find the value of \( R \) that maximizes \( P \), take the derivative of \( P \) with respect to \( R \) and set it equal to zero. Use the quotient rule for differentiation: \( \frac{d}{dR} \left( \frac{\varepsilon^2 R}{(R + r)^2} \right) = 0 \). Solve this equation for \( R \).
Step 5: After solving the derivative equation, you will find that the power is maximized when \( R = r \). This result is known as the condition for maximum power transfer, which states that the load resistance should equal the internal resistance of the battery for maximum power dissipation.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
6m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Ohm's Law

Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. This relationship is expressed as V = IR. Understanding this law is crucial for analyzing circuits, as it helps determine how voltage, current, and resistance interact.
Recommended video:
Guided course
03:07
Resistance and Ohm's Law

Power in Electrical Circuits

The power (P) dissipated in a resistor is given by the formula P = I²R, where I is the current through the resistor and R is its resistance. In the context of load resistors, maximizing power dissipation involves finding the optimal resistance value that allows for the most efficient conversion of electrical energy into heat or work, which is essential for circuit design.
Recommended video:
Guided course
06:18
Power in Circuits

Maximum Power Transfer Theorem

The Maximum Power Transfer Theorem states that maximum power is delivered to a load when the load resistance (R) is equal to the internal resistance (r) of the source. This principle is vital for optimizing circuit performance, as it guides the selection of load resistors to ensure that the maximum possible power is transferred from the source to the load.
Recommended video:
Related Practice
Textbook Question

What are the battery current Ibat and the potential difference V₁ - V₂ between points 1 and 2 when the switch in FIGURE P28.55 is (a) open and (b) closed?

Textbook Question

A small toaster that operates at 120 V has a heating element made from a 4.4-m-long, 0.70-mm-diameter nichrome wire. The resistivity, density, and specific heat of nichrome are, respectively, 1.5 x 10⁻⁶ Ωm, 8400 kg/m³, and 450 J/kg K. If half the heat energy is lost to the air, how long does it take the heating element to warm from 20℃ to 450℃, about the temperature at which it first begins to glow red?

2
views
Textbook Question

A lightbulb is in series with a 2.0 Ω resistor. The lightbulb dissipates 10 W when this series circuit is connected to a 9.0 V battery. What is the current through the lightbulb? There are two possible answers; give both of them.

Textbook Question

Suppose you have resistors 2.5 Ω, 3.5 Ω, and 4.5 Ω and a 100 V power supply. What is the ratio of the total power delivered to the resistors if they are connected in parallel to the total power delivered if they are connected in series?

2
views
Textbook Question

What is the current through the 10 Ω resistor in FIGURE P28.61? Is the current from left to right or right to left?

Textbook Question

A circuit you're building needs an ammeter that goes from 0 mA to a full-scale reading of 50 mA. Unfortunately, the only ammeter in the storeroom goes from 0 μA to a full-scale reading of only 500 μA. Fortunately, you've just finished a physics class, and you realize that you can make this ammeter work by putting a resistor in parallel with it, as shown in FIGURE P28.56. You've measured that the resistance of the ammeter is 50.0 Ω, not the 0 Ω of an ideal ammeter. What is the effective resistance of your ammeter?

1
views