Skip to main content
Ch 08: Dynamics II: Motion in a Plane
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 8, Problem 26

A heavy ball with a weight of 100 N (m = 10.2 kg) is hung from the ceiling of a lecture hall on a 4.5-m-long rope. The ball is pulled to one side and released to swing as a pendulum, reaching a speed of 5.5 m/s as it passes through the lowest point. What is the tension in the rope at that point?

Verified step by step guidance
1
Step 1: Identify the forces acting on the ball at the lowest point of the swing. These include the gravitational force (weight) acting downward and the tension in the rope acting upward. Additionally, the ball experiences a centripetal force due to its circular motion.
Step 2: Write the equation for the net force in the vertical direction at the lowest point. The net force is the centripetal force, which is provided by the difference between the tension in the rope and the gravitational force. Mathematically, this can be expressed as: T - W = mv^2r, where T is the tension, W is the weight, m is the mass, v is the speed, and r is the radius of the circular motion (equal to the length of the rope).
Step 3: Rearrange the equation to solve for the tension T. This gives: T = W + mv^2r. Substitute the known values: W = 100 N, m = 10.2 kg, v = 5.5 m/s, and r = 4.5 m.
Step 4: Calculate the centripetal force term mv^2r. This involves squaring the speed (v^2), multiplying by the mass (m), and dividing by the radius (r).
Step 5: Add the gravitational force (W) to the centripetal force term to find the total tension (T) in the rope. Ensure that the units are consistent throughout the calculation.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
5m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Newton's Second Law of Motion

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This principle is crucial for analyzing forces acting on the pendulum at the lowest point of its swing, where both gravitational and tension forces are at play.
Recommended video:
Guided course
06:54
Intro to Forces & Newton's Second Law

Centripetal Force

Centripetal force is the net force required to keep an object moving in a circular path, directed towards the center of the circle. In the case of the pendulum, as the ball swings through the lowest point, the tension in the rope provides the necessary centripetal force to maintain its circular motion.
Recommended video:
Guided course
06:48
Intro to Centripetal Forces

Energy Conservation

The principle of energy conservation states that energy cannot be created or destroyed, only transformed from one form to another. As the pendulum swings, potential energy at the highest point converts to kinetic energy at the lowest point, allowing us to analyze the forces acting on the ball and calculate the tension in the rope.
Recommended video:
Guided course
06:24
Conservation Of Mechanical Energy
Related Practice
Textbook Question

A toy train rolls around a horizontal 1.0-m-diameter track. The coefficient of rolling friction is 0.10. How long does it take the train to stop if it's released with an angular speed of 30 rpm?

1
views
Textbook Question

You are driving your 1800 kg car at 25 m/s over a circular hill that has a radius of 150 m. A deer running across the road causes you to hit the brakes hard while right at the summit of the hill, and you start to skid. The coefficient of kinetic friction between your tires and the road is 0.75. What is the magnitude of your acceleration as you begin to slow?

2
views
Textbook Question

The normal force equals the magnitude of the gravitational force as a roller-coaster car crosses the top of a 40-m-diameter loop-the-loop. What is the car's speed at the top?

1
views
Textbook Question

A 500 g ball moves in a vertical circle on a 102-cm-long string. If the speed at the top is 4.0 m/s, then the speed at the bottom will be 7.5 m/s. (You'll learn how to show this in Chapter 10.) What is the tension in the string when the ball is at the top?

1
views
Textbook Question

A new car is tested on a 200-m-diameter track. If the car speeds up at a steady 1.5 m/s2, how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?

1
views
Textbook Question

A 500 g ball moves in a vertical circle on a 102-cm-long string. If the speed at the top is 4.0 m/s, then the speed at the bottom will be 7.5 m/s. (You'll learn how to show this in Chapter 10.) What is the gravitational force acting on the ball?

1
views