Textbook Question
A woman has a mass of 55 kg. What is her weight while standing on earth?
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Ch 06: Dynamics I: Motion Along a Line
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796
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Table of contents
- Ch 01: Concepts of Motion35
- Ch 02: Kinematics in One Dimension75
- Ch 03: Vectors and Coordinate Systems58
- Ch 04: Kinematics in Two Dimensions60
- Ch 05: Force and Motion23
- Ch 06: Dynamics I: Motion Along a Line53
- Ch 07: Newton's Third Law27
- Ch 08: Dynamics II: Motion in a Plane52
- Ch 09: Work and Kinetic Energy56
- Ch 10: Interactions and Potential Energy50
- Ch 11: Impulse and Momentum56
- Ch 12: Rotation of a Rigid Body71
- Ch 13: Newton's Theory of Gravity52
- Ch 14: Fluids and Elasticity44
- Ch 15: Oscillations55
- Ch 16: Traveling Waves37
- Ch 17: Superposition39
- Ch 18: A Macroscopic Description of Matter53
- Ch 19: Work, Heat, and the First Law of Thermodynamics60
- Ch 20: The Micro/Macro Connection53
- Ch 21: Heat Engines and Refrigerators34
- Ch 22: Electric Charges and Forces40
- Ch 23: The Electric Field39
- Ch 24: Gauss' Law32
- Ch 25: The Electric Potential63
- Ch 26: Potential and Field57
- Ch 27: Current and Resistance42
- Ch 28: Fundamentals of Circuits39
- Ch 29: The Magnetic Field47
- Ch 30: Electromagnetic Induction60
- Ch 31: Electromagnetic Fields and Waves32
- Ch 32: AC Circuits63
- Ch 33: Wave Optics32
- Ch 34: Ray Optics57
- Ch 35: Optical Instruments30
- Ch 36: Special Relativity38
- Ch 37: The Foundations of Modern Physics25
- Ch 38: Quantization49
- Ch 39: Wave Functions and Uncertainty31
- Ch 40: One-Dimensional Quantum Mechanics35
- Ch 41: Atomic Physics18
- Ch 42: Nuclear Physics27
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 6, Problem 18a
It takes the elevator in a skyscraper 4.0 s to reach its cruising speed of 10 m/s. A 60 kg passenger gets aboard on the ground floor. What is the passenger's weight before the elevator starts moving?
Verified step by step guidance1
Determine the passenger's weight before the elevator starts moving. Weight is the force due to gravity acting on the passenger, which is calculated using the formula: , where is the mass of the passenger and is the acceleration due to gravity.
Substitute the given values into the formula. The mass of the passenger is kg, and the acceleration due to gravity is approximately m/s².
Perform the multiplication: . This will give the weight of the passenger in newtons (N).
Since the elevator has not started moving yet, there are no additional forces acting on the passenger other than gravity. Therefore, the calculated weight is the passenger's weight before the elevator starts moving.
Conclude that the passenger's weight before the elevator starts moving is solely determined by the gravitational force acting on their mass.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Weight
Weight is the force exerted by gravity on an object, calculated as the product of mass and the acceleration due to gravity. It is given by the formula W = mg, where W is weight, m is mass, and g is approximately 9.81 m/s² on the surface of the Earth. For a 60 kg passenger, their weight can be determined by multiplying their mass by the gravitational acceleration.
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Torque Due to Weight
Mass
Mass is a measure of the amount of matter in an object, typically measured in kilograms. Unlike weight, mass does not change regardless of the object's location in the universe. It is a scalar quantity and is fundamental in determining the weight of an object when combined with the acceleration due to gravity.
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Gravitational Acceleration
Gravitational acceleration is the acceleration experienced by an object due to the force of gravity. On Earth, this value is approximately 9.81 m/s², meaning that an object will accelerate downwards at this rate if in free fall. This constant is crucial for calculating weight, as it directly influences the force exerted on an object's mass.
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Related Practice
Textbook Question
The position of a 2.0 kg mass is given by x = (2t3 - 3t2) where t is in seconds. What is the net horizontal force on the mass at t = 1s?
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Textbook Question
FIGURE EX6.19 shows the velocity graph of a 75 kg passenger in an elevator. What is the passenger's weight at t=1s? At 5 s? At 9 s?
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Textbook Question
A 50 kg box hangs from a rope. What is the tension in the rope if: The box has vy = 5.0 m/s and is speeding up at 5.0 m/s2
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Textbook Question
Zach, whose mass is 80 kg, is in an elevator descending at 10 m/s. The elevator takes 3.0 s to brake to a stop at the first floor. What is Zach's weight before the elevator starts braking?
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Textbook Question
It takes the elevator in a skyscraper 4.0 s to reach its cruising speed of 10 m/s. A 60 kg passenger gets aboard on the ground floor. What is the passenger's weight after the elevator reaches its cruising speed?
2
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