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Ch. 03 - Kinematics in Two or Three Dimensions; Vectors
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Not the one you use?Change textbook
Chapter 3, Problem 33

A diver running 2.5 m/s dives out horizontally from the edge of a vertical cliff and 3.5 s later reaches the water below. How high was the cliff and how far from its base did the diver hit the water?

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Determine the height of the cliff using the vertical motion of the diver. Since the diver starts with no initial vertical velocity, use the kinematic equation for vertical displacement: y = 12gt2, where g is the acceleration due to gravity (9.8 m/s²) and t is the time (3.5 s).
Substitute the values into the equation: y = 12(9.8)(3.52). This will give the height of the cliff.
Determine how far from the base of the cliff the diver lands by analyzing the horizontal motion. Use the equation for horizontal displacement: x = v0t, where v0 is the initial horizontal velocity (2.5 m/s) and t is the time (3.5 s).
Substitute the values into the equation: x = (2.5)(3.5). This will give the horizontal distance traveled by the diver.
Combine the results from the vertical and horizontal motion to fully describe the diver's trajectory. The height of the cliff corresponds to the vertical displacement, and the distance from the base corresponds to the horizontal displacement.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Projectile Motion

Projectile motion refers to the motion of an object that is launched into the air and is subject to the force of gravity. In this scenario, the diver's horizontal velocity remains constant while the vertical motion is influenced by gravitational acceleration. Understanding the separation of horizontal and vertical components is crucial for analyzing the diver's trajectory.
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Kinematic Equations

Kinematic equations describe the motion of objects under constant acceleration. For vertical motion, the equation h = 0.5 * g * t^2 can be used to calculate the height of the cliff, where h is the height, g is the acceleration due to gravity (approximately 9.81 m/s²), and t is the time of fall. These equations allow us to relate time, distance, and acceleration.
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Horizontal Distance Calculation

The horizontal distance traveled by the diver can be calculated using the formula d = v * t, where d is the distance, v is the horizontal velocity, and t is the time of flight. Since the diver runs at a constant speed of 2.5 m/s for 3.5 seconds, this concept helps determine how far from the base of the cliff the diver lands in the water.
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Textbook Question

A stunt driver wants to make his car jump over 8 cars parked side by side below a horizontal ramp (Fig. 3–46). With what minimum speed must he drive off the horizontal ramp? The vertical height of the ramp is 1.5 m above the car roofs and the horizontal distance he must clear is 22 m. 

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Textbook Question

At serve, a tennis player aims to hit the ball horizontally. What minimum speed is required for the ball to clear the 0.90-m-high net about 15.0 m from the server if the ball is 'launched' from a height of 2.30 m? Where will the ball land if it just clears the net (and will it be 'good' in the sense that it lands within 7.0 m of the net)? How long will it be in the air? See Fig. 3–50.

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Textbook Question

A car is moving with speed 16.0 m/s due south at one moment and 25.7 m/s due east 8.00 s later. Over this time interval, determine the magnitude and direction of (a) its average velocity, (b) its average acceleration. (c) What is its average speed? [Hint: Can you determine all these from the information given?]

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Textbook Question

A motorboat whose speed in still water is 4.30 m/s must aim upstream at an angle of 23.5° (with respect to a line perpendicular to the shore) in order to travel directly across the stream. What is the resultant speed of the boat with respect to the shore? (See Fig. 3–33.)

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Textbook Question

A skier is accelerating down a 30.0° hill at 1.80 m/s² (Fig. 3–42). What is the vertical component of her acceleration?

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Textbook Question

A skier is accelerating down a 30.0° hill at 1.80 m/s² (Fig. 3–42). How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 125 m? 

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