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Ch. 02 - Describing Motion: Kinematics in One Dimension
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Not the one you use?Change textbook
Chapter 2, Problem 87b

Two children are playing on two trampolines. The first child bounces up one-and-a-half times higher than the second child. The initial speed upwards of the second child is 4.0 m/s. What is the initial speed of the first child?

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Step 1: Recall the kinematic equation for vertical motion under constant acceleration due to gravity: h = \(\frac{v_0^2}{2g}\), where h is the maximum height, v_0 is the initial velocity, and g is the acceleration due to gravity (approximately 9.8 \ \(\text{m/s}\)^2).
Step 2: Let the maximum height reached by the second child be h_2. Using the given initial velocity of the second child, v_{0,2} = 4.0 \ \(\text{m/s}\), substitute into the equation: h_2 = \(\frac{(4.0)^2}{2 \cdot 9.8}\). This gives the height h_2 in terms of known values.
Step 3: The problem states that the first child bounces one-and-a-half times higher than the second child. Therefore, the maximum height of the first child is h_1 = 1.5 \(\cdot\) h_2. Substitute h_2 from Step 2 into this equation to express h_1 in terms of known values.
Step 4: Using the same kinematic equation for the first child, h_1 = \(\frac{v_{0,1}\)^2}{2g}, solve for the initial velocity of the first child: v_{0,1} = \(\sqrt{2g \cdot h_1}\). Substitute h_1 from Step 3 into this equation.
Step 5: Simplify the expression for v_{0,1} to find the initial velocity of the first child in terms of the given values. This will provide the relationship between the initial velocities of the two children.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Kinematics

Kinematics is the branch of mechanics that deals with the motion of objects without considering the forces that cause the motion. It involves concepts such as displacement, velocity, and acceleration. In this scenario, understanding kinematics is essential to relate the initial speed of the second child to the height achieved by both children on the trampolines.
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Potential Energy and Height

Potential energy is the energy stored in an object due to its position in a gravitational field, which is directly related to its height. The higher an object is raised, the more potential energy it possesses. In this case, the height reached by the first child, who bounces higher than the second, can be calculated using the relationship between initial speed and potential energy at the peak of the bounce.
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Energy Conservation

The principle of energy conservation states that energy cannot be created or destroyed, only transformed from one form to another. In the context of the trampolines, the kinetic energy of the children at the moment of takeoff is converted into potential energy at the peak of their jumps. This principle allows us to relate the initial speeds of both children based on the heights they achieve.
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Related Practice
Textbook Question

A robot used in a pharmacy picks up a medicine bottle at t = 0. It accelerates at 0.20 m/s² for 4.5 s, then travels without acceleration for 68 s and finally decelerates at ―0.40 m/s² for 2.5 s to reach the counter where the pharmacist will take the medicine from the robot. From how far away did the robot fetch the medicine?

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Textbook Question

A police car at rest is passed by a speeder traveling at a constant 140 km/h. The police officer takes off in hot pursuit and catches up to the speeder in 850 m, maintaining a constant acceleration. Qualitatively plot the position vs. time graph for both cars from the police car's start to the catch-up point.

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Textbook Question

The position of a ball rolling in a straight line is given by 𝓍 = 2.0 ― 3.6t + 1.7t², where 𝓍 is in meters and t in seconds. What do the numbers 2.0, 3.6, and 1.7 refer to?

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Textbook Question

A parachutist bails out of an airplane, and freely falls 75 m (ignore air friction). Then the parachute opens, and her acceleration is ― 1.5 m/s² (up). The parachutist reaches the ground with a speed of 1.5 m/s. From how high did she bail out of the plane?

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Textbook Question

Air resistance acting on a falling body can be taken into account by the approximate relation for the acceleration: a = dv/dt = g ― kv, where k is a constant. Determine an expression for the terminal velocity, which is the maximum value the velocity reaches.

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Textbook Question

Suppose a 65-kg person jumps from a height of 3.0 m down to the ground. What is the speed of the person just before landing (Chapter 2)?

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