Acceleration at the Highest Point: When an object is thrown upward, its acceleration at the highest point is equal to the acceleration due to gravity, directed downward. a=-9.8 m/s2

Stopping Distance with Constant Acceleration: The distance required for an object to stop under constant acceleration can be found using: vf2=vi+2ad, where vf is final velocity (0 when stopping), vi is initial velocity, a is acceleration, and d is distance.

Distance Traveled with Constant Acceleration: For an object accelerating from an initial velocity vi to a final velocity vf over time t, the distance is: d=0.5(vi+vf)t

Finding Initial Speed from Distance and Acceleration: When given distance, acceleration, and change in velocity, use kinematic equations to solve for unknowns. Rearranging d=0.5(vi+vf)t or vf=vi+2ad as needed.

Distance Traveled Under Constant Acceleration: For an object starting from rest or with initial velocity, the distance after time t is: d=vit+0.5at2