A spherically symmetric charge distribution produces the electric field N/C, where r is in m. How much charge is inside this 40-cm-diameter spherical surface?
24. Electric Force & Field; Gauss' Law
Electric Flux
- Textbook Question1views
- Textbook Question
A flat sheet of paper of area m2 is oriented so that the normal to the sheet is at an angle of ° to a uniform electric field of magnitude N/C. For what angle between the normal to the sheet and the electric field is the magnitude of the flux through the sheet (i) largest and (ii) smallest? Explain your answers.
2views - Multiple ChoiceA cube has sides of . Inside the cube is a and a charge. What is the net flux through the cube?1views
- Textbook Question
The cube in FIGURE EX24.7 contains negative charge. The electric field is constant over each face of the cube. Does the missing electric field vector on the front face point in or out? What strength must this field exceed?
1views - Multiple Choice
Given a uniform electric field perpendicular to the plane of an annular ring (surface ) with inner radius and outer radius , what is the electric flux through the ring if the electric field has magnitude and points outward from the surface?
- Multiple Choice
Which of the following correctly describes the electric flux through a flat surface of area placed perpendicular to a uniform electric field ?
1views - Multiple Choice
What is the total flux through the two surfaces depicted in the following figure? Note that surface 1 has an area of 50 cm2 and surface 2 has an area of 100 cm2 , and E = 500 N/C.
1views - Multiple Choice
A point charge of is placed at the center of a closed spherical surface. What is the electric flux through the surface?
1views - Textbook Question
All examples of Gauss’s law have used highly symmetric surfaces where the flux integral is either zero or EA. Yet we’ve claimed that the net Φₑ = Qᵢₙ / ϵ₀ is independent of the surface. This is worth checking. FIGURE CP24.57 shows a cube of edge length L centered on a long thin wire with linear charge density λ. The flux through one face of the cube is not simply EA because, in this case, the electric field varies in both strength and direction. But you can calculate the flux by actually doing the flux integral. Now integrate dΦ to find the total flux through this face.
- Multiple Choice
A uniform electric field points vertically upward. Cylinder (a) in Figure 1 is oriented so its axis is horizontal and its ends are perpendicular to the field lines. What is the net electric flux through cylinder (a)?
- Textbook Question
A 10 nC charge is at the center of a 2.0 m x 2.0 m x 2.0 m cube. What is the electric flux through the top surface of the cube?
22views - Textbook Question
Find the electric fluxes ΦA to ΦE through surfaces A to E in FIGURE P24.29.
- Multiple Choice
An infinite line of charge with linear charge density passes along the axis of a cylindrical surface of radius and length . What is the electric flux through the curved surface of the cylinder due to the line of charge?
- Multiple Choice
A uniform electric field of magnitude points perpendicular to the plane of a circular loop of radius . What is the electric flux through the loop?
- Textbook QuestionA spherically symmetric charge distribution produces the electric field E (→ above E) = (5000r²) rˆ N/C, where r is in m. (b) What is the electric flux through a 40-cm-diameter spherical surface that is concentric with the charge distribution?1views