-position-is-xt-3t2-2t-1-meters-what-is-its-average-velocity-from-t-1-s-to-t-3-s

Question

An object's position is x(t)=3t2−2t+1x(t) = $$3t^2 - 2t + 1 $$meters. What is its average velocity from t=1t = 1 s	ext{s} to t=3t = 3 s	ext{s}?

Accepted Answer

1010 m/s	ext{m/s}

Answer

2020 m/s	ext{m/s}

Answer

88 m/s	ext{m/s}

Answer

66 m/s	ext{m/s}

An object's position is x(t)=3t2−2t+1x(t) = 3t^2 - 2t + 1 meters. What is its average velocity from t=1t = 1 s\(\text{s}\) to t=3t = 3 s\(\text{s}\)?