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Ch 03: Motion in Two or Three Dimensions
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 3, Problem 7c

The coordinates of a bird flying in the xy-plane are given by x(t) = αt and y(t) = 3.0 m − βt2, where α = 2.4 m/s and β = 1.2 m/s2. Calculate the magnitude and direction of the bird's velocity and acceleration at t = 2.0 s.

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First, determine the velocity components of the bird. The velocity in the x-direction, v_x(t), is the derivative of x(t) with respect to time t. Since x(t) = αt, the derivative is v_x(t) = α. Similarly, the velocity in the y-direction, v_y(t), is the derivative of y(t) with respect to time t. Given y(t) = 3.0 m − βt², the derivative is v_y(t) = -2βt.
Next, calculate the velocity components at t = 2.0 s. Substitute t = 2.0 s into the expressions for v_x(t) and v_y(t). For v_x(t), it remains constant as α = 2.4 m/s. For v_y(t), substitute t = 2.0 s into v_y(t) = -2βt to find v_y(2.0 s).
To find the magnitude of the bird's velocity at t = 2.0 s, use the Pythagorean theorem. The magnitude of the velocity vector v is given by v = √(v_x² + v_y²). Substitute the values of v_x and v_y at t = 2.0 s into this formula.
Determine the direction of the bird's velocity at t = 2.0 s. The direction θ can be found using the tangent function: θ = arctan(v_y/v_x). Substitute the values of v_y and v_x at t = 2.0 s into this formula to find the angle θ.
Finally, calculate the acceleration components. The acceleration in the x-direction, a_x(t), is the derivative of v_x(t) with respect to time, which is zero since v_x(t) is constant. The acceleration in the y-direction, a_y(t), is the derivative of v_y(t) with respect to time, which is a_y(t) = -2β. Calculate a_y(t) at t = 2.0 s using β = 1.2 m/s².

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Velocity in Two Dimensions

Velocity in two dimensions involves both the x and y components, which can be derived from the derivatives of the position functions with respect to time. For the bird's motion, the velocity components are vx = dx/dt = α and vy = dy/dt = -2βt. The magnitude of the velocity is found using the Pythagorean theorem: v = √(vx² + vy²).
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Acceleration in Two Dimensions

Acceleration in two dimensions also has x and y components, obtained from the second derivatives of the position functions. For the bird, the acceleration components are ax = d²x/dt² = 0 and ay = d²y/dt² = -2β. The magnitude of the acceleration is calculated similarly to velocity: a = √(ax² + ay²).
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Direction of a Vector

The direction of a vector in the xy-plane is determined by the angle it makes with the positive x-axis, calculated using trigonometry. For velocity and acceleration, the angle θ can be found using tan(θ) = vy/vx for velocity and tan(θ) = ay/ax for acceleration. This angle provides insight into the vector's orientation relative to the coordinate axes.
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Related Practice
Textbook Question

A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by v=[5.00 m/s(0.0180 m/s3)t2]i^+[2.00 m/s+(0.550 m/s2)t]j^\(\vec{v}\) = \(\left\)[ 5.00~\(\mathrm{m/s}\) - (0.0180~\(\mathrm{m/s^3}\))t^2 \(\right\)] \(\hat{i}\) + \(\left\)[ 2.00~\(\mathrm{m/s}\) + (0.550~\(\mathrm{m/s^2}\))t \(\right\)] \(\hat{j}\). What are the magnitude and direction of the car's velocity at t=8.00 st=8.00\(\text{ }\)s? (b) What are the magnitude and direction of the car's acceleration at t=8.00 st=8.00\(\text{ }\)s?

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Textbook Question

The coordinates of a bird flying in the xy-plane are given by x(t) = αt and y(t) = 3.0 m − βt2, where α = 2.4 m/s and β = 1.2 m/s2. (a) Sketch the path of the bird between t = 0 and t = 2.0 s.

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Textbook Question

The coordinates of a bird flying in the xy-plane are given by x(t) = αt and y(t) = 3.0 m − βt2, where α = 2.4 m/s and β = 1.2 m/s2. Calculate the velocity and acceleration vectors of the bird as functions of time.

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Textbook Question

A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by v=[5.00 m/s(0.0180 m/s3)t2]i^+[2.00 m/s+(0.550 m/s2)t]j^\(\vec{v}\) = \(\left\)[ 5.00~\(\mathrm{m/s}\) - (0.0180~\(\mathrm{m/s^3}\))t^2 \(\right\)] \(\hat{i}\) + \(\left\)[ 2.00~\(\mathrm{m/s}\) + (0.550~\(\mathrm{m/s^2}\))t \(\right\)] \(\hat{j}\). What are ax(t)a_{x}(t) and ay(t)a_{y}(t), the xx- and yy- components of the car's velocity as functions of time?

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Textbook Question

A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.480 s. Ignore air resistance. Find the height of the tabletop above the floor.

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Textbook Question

A dog running in an open field has components of velocity vx = 2.6 m/s and vy = −1.8 m/s at t1 = 10.0 s. For the time interval from t1 = 10.0 s to t2 = 20.0 s, the average acceleration of the dog has magnitude 0.45 m/s2 and direction 31.0° measured from the +x–axis toward the +y–axis. At t2 = 20.0 s, what are the x- and y-components of the dog's velocity?

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