Textbook Question
Classify each reaction as a substitution, an elimination, or neither. Identify the leaving group in each reaction, and the nucleophile in substitutions.
c.
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Ch.6 - Alkyl Halides; Nucleophilic Substitution
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 6, Problem 13a
Under certain conditions, the reaction of 0.5 M 1-bromobutane with 1.0 M sodium methoxide forms 1-methoxybutane at a rate of 0.05 mol/L per second. What would be the rate if 0.1 M 1-bromobutane and 2.0 M NaOCH3 were used?
Verified step by step guidance1
Identify the type of reaction: The reaction involves 1-bromobutane (an alkyl halide) and sodium methoxide (a strong nucleophile). This suggests an SN2 reaction, which is second-order overall, meaning the rate depends on the concentrations of both reactants.
Write the rate law for the reaction: The rate law for an SN2 reaction is given by \( \text{Rate} = k[\text{1-bromobutane}][\text{NaOCH}_3] \), where \( k \) is the rate constant.
Determine the rate constant \( k \): Using the initial conditions provided, substitute \( \text{Rate} = 0.05 \ \text{mol/L/s} \), \( [\text{1-bromobutane}] = 0.5 \ \text{M} \), and \( [\text{NaOCH}_3] = 1.0 \ \text{M} \) into the rate law to solve for \( k \). Rearrange the equation to \( k = \frac{\text{Rate}}{[\text{1-bromobutane}][\text{NaOCH}_3]} \).
Substitute the new concentrations into the rate law: Once \( k \) is determined, use the new concentrations \( [\text{1-bromobutane}] = 0.1 \ \text{M} \) and \( [\text{NaOCH}_3] = 2.0 \ \text{M} \) in the rate law \( \text{Rate} = k[\text{1-bromobutane}][\text{NaOCH}_3] \).
Calculate the new rate: Multiply the value of \( k \) by the new concentrations of 1-bromobutane and sodium methoxide to find the new rate of the reaction.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Reaction Rate
The reaction rate is a measure of how quickly reactants are converted into products in a chemical reaction. It is typically expressed in terms of concentration change over time, such as mol/L per second. Understanding how concentration affects the rate is crucial, as it can be influenced by factors like reactant concentration, temperature, and the presence of catalysts.
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Rates of Intramolecular Reactions Concept 2
Concentration and Stoichiometry
Concentration refers to the amount of a substance in a given volume of solution, usually expressed in molarity (M). In this reaction, the stoichiometry dictates how the concentrations of 1-bromobutane and sodium methoxide will affect the formation of 1-methoxybutane. Adjusting the concentrations of reactants can lead to different reaction rates, which is essential for predicting outcomes in chemical reactions.
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Rate Law
The rate law is an equation that relates the rate of a reaction to the concentration of its reactants, typically expressed as rate = k[A]^m[B]^n, where k is the rate constant, and m and n are the reaction orders with respect to each reactant. Understanding the rate law allows chemists to predict how changes in concentration will affect the reaction rate, which is key to solving the given problem.
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5:07Rates of Intramolecular Reactions Concept 2
Related Practice
Textbook Question
Classify each reaction as a substitution, an elimination, or neither. Identify the leaving group in each reaction, and the nucleophile in substitutions.
b.
1
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Textbook Question
Classify each reaction as a substitution, an elimination, or neither. Identify the leaving group in each reaction, and the nucleophile in substitutions.
a.
1
views
Textbook Question
Under certain conditions, the reaction of 0.5 M 1-bromobutane with 1.0 M sodium methoxide forms 1-methoxybutane at a rate of 0.05 mol/L per second.
c. Show another SN2 reaction using a different combination of an alkoxide and an alkyl bromide that also produces 1-methoxybutane.
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Textbook Question
Consider the reaction of 1-bromobutane with a large excess of ammonia (NH3). Draw the reactants, the transition state, and the products. Note that the initial product is the salt of an amine (RNH3+Br−), which is deprotonated by the excess ammonia to give the amine.
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Textbook Question
Predict the major products of the following substitutions.
a.
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