Textbook Question
Show how you would convert
a. oct-3-yne to cis-oct-3-ene.
b. pent-2-yne to trans-pent-2-ene.
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Ch.9 - Alkynes
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 9, Problem 10
When 2,2-dibromo-1-phenylpropane is heated overnight in fused KOH at 200 C, the major product is a foul-smelling compound of formula C9H8. Propose a structure for this product, and give a mechanism to account for its formation.
Problem-Solving Hint:
Verified step by step guidance1
Step 1: Analyze the given compound, 2,2-dibromo-1-phenylpropane. The presence of two bromine atoms on the same carbon suggests that elimination reactions can occur to form a triple bond (alkyne).
Step 2: Recognize the reaction conditions. Fused KOH at 200 °C is a strong base and high temperature promotes elimination reactions. This setup favors the formation of the most stable internal alkyne.
Step 3: Propose the mechanism. The reaction proceeds via a double dehydrohalogenation mechanism. First, KOH abstracts a proton from the carbon adjacent to the bromine atoms, leading to the formation of a carbanion. This carbanion eliminates a bromide ion, forming a double bond. The process repeats to eliminate the second bromine atom, resulting in the formation of a triple bond.
Step 4: Determine the major product. The most stable internal alkyne is formed due to the conjugation with the phenyl group. The product has the formula C9H8, which corresponds to phenylacetylene (C6H5-C≡CH).
Step 5: Explain the foul smell. Phenylacetylene is known to have a strong, unpleasant odor, consistent with the description in the problem.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Elimination Reactions
Elimination reactions involve the removal of atoms or groups from a molecule, resulting in the formation of a double or triple bond. In the case of 2,2-dibromo-1-phenylpropane, heating with KOH promotes the elimination of bromine atoms, leading to the formation of alkenes or alkynes. Understanding the mechanism of elimination is crucial for predicting the structure of the product formed.
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00:40
Recognizing Elimination Reactions.
Alkyne Stability
Alkynes can be classified as terminal or internal based on the position of the triple bond. Internal alkynes, which have the triple bond between two carbon atoms, are generally more stable than terminal alkynes, which have the triple bond at the end of the carbon chain. The stability influences the product distribution in elimination reactions, making it essential to consider when predicting the major product.
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03:43The radical stability trend.
Mechanism of Dehydrohalogenation
Dehydrohalogenation is a specific type of elimination reaction where a hydrogen halide is removed from a haloalkane, resulting in the formation of alkenes or alkynes. The mechanism typically involves the formation of a double bond through the loss of a halogen and a hydrogen atom. In this case, the mechanism helps explain how the foul-smelling compound C9H8 is formed from 2,2-dibromo-1-phenylpropane under the reaction conditions provided.
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03:02The dehydrohalogenation mechanism.
Related Practice
Textbook Question
When 2,2-dibromo-1-phenylpropane is heated overnight with sodium amide at 150°C, the major product (after addition of water) is a different foul-smelling compound of formula C9H8. Propose a structure for this product, and give a mechanism to account for its formation.
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Textbook Question
Show how you would synthesize each compound, beginning with acetylene and any necessary additional reagents
(c)
(d)
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Textbook Question
Show how you would convert
c. cis-cyclodecene to trans-cyclodecene.
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Textbook Question
Show how you would synthesize each compound, beginning with acetylene and any necessary additional reagents
(b)
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Textbook Question
Show how you would synthesize 2-phenylhex-3-yn-2-ol, starting with acetophenone (PhCOCH3) and any other reagents you need. ("2-ol" means there is an OH group on C2.)
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