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Ch.4 - The Study of Chemical Reactions
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 4, Problem 7a

When ethene is mixed with hydrogen in the presence of a platinum catalyst, hydrogen adds across the double bond to form ethane. At room temperature, the reaction goes to completion. Predict the signs of ΔH° and ΔS° for this reaction. Explain these signs in terms of bonding and freedom of motion.

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Step 1: Analyze the reaction. The reaction involves the addition of hydrogen (H₂) to ethene (C₂H₄) in the presence of a platinum catalyst, resulting in the formation of ethane (C₂H₆). This is a hydrogenation reaction where the double bond in ethene is converted into a single bond in ethane.
Step 2: Predict the sign of ΔH°. The reaction involves breaking the π bond in the double bond of ethene and forming two new C-H σ bonds in ethane. Since σ bonds are stronger and more stable than π bonds, the reaction releases energy. Therefore, ΔH° (enthalpy change) is negative, indicating an exothermic reaction.
Step 3: Predict the sign of ΔS°. The reaction starts with two reactant molecules (ethene and H₂) and produces one product molecule (ethane). This reduction in the number of molecules leads to a decrease in the system's randomness or disorder. Therefore, ΔS° (entropy change) is negative.
Step 4: Explain ΔH° in terms of bonding. The breaking of the weaker π bond in ethene and the formation of stronger C-H σ bonds in ethane result in a net release of energy, making the reaction exothermic (negative ΔH°).
Step 5: Explain ΔS° in terms of freedom of motion. The reactants (ethene and H₂) have more freedom of motion as separate molecules compared to the single product (ethane). This reduction in molecular freedom leads to a decrease in entropy (negative ΔS°).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Enthalpy Change (ΔH°)

The enthalpy change (ΔH°) of a reaction indicates whether the reaction is exothermic or endothermic. In the case of the hydrogenation of ethene to form ethane, the reaction releases energy as new C-H bonds are formed, resulting in a negative ΔH°. This signifies that the products are more stable than the reactants due to the formation of stronger bonds.
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Entropy Change (ΔS°)

Entropy change (ΔS°) measures the disorder or randomness in a system. In the hydrogenation reaction, two gaseous reactants (ethene and hydrogen) combine to form one gaseous product (ethane), leading to a decrease in the number of gas molecules. This results in a negative ΔS°, indicating a reduction in the system's disorder as the reaction proceeds.
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Catalysis

Catalysis involves the use of a catalyst to increase the rate of a chemical reaction without being consumed in the process. In this reaction, platinum acts as a catalyst, facilitating the addition of hydrogen across the double bond of ethene. The presence of the catalyst lowers the activation energy required for the reaction, allowing it to proceed more efficiently at room temperature.
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Related Practice
Textbook Question

The following reaction has a value of ΔG° = –2.1 kJ/mol (–0.50 kcal/mol).

CH3Br + H2S ⇌ CH3SH + HBr

b. Starting with a 1 M solution of CH3Br and H2S, calculate the final concentrations of all four species at equilibrium.

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Textbook Question

Under base-catalyzed conditions, two molecules of acetone can condense to form diacetone alcohol. At room temperature (25 °C), about 5% of the acetone is converted to diacetone alcohol. Determine the value of ΔG° for this reaction.

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Textbook Question

For each reaction, estimate whether ΔS° for the reaction is positive, negative, or impossible to predict.

(a)

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Textbook Question

Draw a reaction-energy diagram for the propagation steps of the free-radical addition of HBr to isobutylene. Draw curves representing the reactions leading to both the Markovnikov and the anti-Markovnikov products. Compare the values of ∆Gº and Ea and for the rate-limiting steps, and explain why only one of these products is observed.

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Textbook Question

For each reaction, estimate whether ΔS° for the reaction is positive, negative, or impossible to predict.

(b)

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Textbook Question
The dehydrogenation of butane to trans-but-2-ene has ΔH° = +116 kJ/mol (+27.6 kcal/mol) and ΔS° = +117J/kelvin-mol (+28.0 cal/kelvin-mol). a. Compute the value of ΔG° for dehydrogenation at room temperature (25 °C or 298 °K). Is dehydrogenation favored or disfavored?HINT: When you are doing synthesis problems, avoid using these high-temperature industrial methods. They require specialized equipment, and they produce variable mixtures of products.