Match four of the following UV absorption maxima (λmax) with the corresponding compounds: (1) 232 nm; (2) 256 nm; (3) 273 nm; (4) 292 nm; (5) 313 nm; (6) 353 nm.
Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy
All textbooks
Wade 9th Edition
Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy
Problem 24
Wade 9th Edition
Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy
Problem 24Chapter 15, Problem 24
Classify the following dienes and polyenes as isolated, conjugated, cumulated, or some combination of these classifications.
(a) cycloocta-1,4-diene
(b) cycloocta-1,3-diene
(c) cyclodeca-1,2-diene
(d) cycloocta-1,3,5,7-tetraene
(e) cyclohexa-1,3,5-triene (benzene)
(f) penta-1,2,4-triene
Verified step by step guidance1
Step 1: Understand the classifications of dienes and polyenes. Isolated dienes have double bonds separated by more than one single bond. Conjugated dienes have alternating single and double bonds. Cumulated dienes have adjacent double bonds. Some molecules may exhibit combinations of these classifications.
Step 2: Analyze structure (a) cycloocta-1,4-diene. The double bonds are separated by two single bonds, making them isolated dienes.
Step 3: Analyze structure (b) cycloocta-1,3-diene. The double bonds are separated by one single bond, forming a conjugated diene.
Step 4: Analyze structure (c) cyclodeca-1,2-diene. The double bonds are adjacent, making this a cumulated diene.
Step 5: Analyze structure (d) cycloocta-1,3,5,7-tetraene and (e) cyclohexa-1,3,5-triene (benzene). Both structures exhibit alternating single and double bonds throughout the ring, classifying them as conjugated polyenes. For structure (f) penta-1,2,4-triene, the molecule contains both cumulated and conjugated double bonds, as the first two double bonds are adjacent (cumulated), and the second and third double bonds are separated by one single bond (conjugated).

Verified video answer for a similar problem:
This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
4mWas this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Diene Classification
Dienes are classified based on the arrangement of their double bonds. Isolated dienes have double bonds separated by more than one single bond, conjugated dienes have alternating double and single bonds, and cumulated dienes have two or more double bonds directly adjacent to each other. Understanding these classifications is essential for predicting reactivity and stability in organic reactions.
Recommended video:
Guided course
Structural Classification
Conjugation
Conjugation occurs when p-orbitals overlap across adjacent double bonds, allowing for delocalization of electrons. This delocalization stabilizes the molecule and can affect its reactivity and color. Conjugated systems often exhibit unique properties, such as lower energy transitions, which are important in fields like organic electronics and photochemistry.
Recommended video:
Guided course
Conjugated states
Cycloalkenes
Cycloalkenes are cyclic compounds that contain one or more double bonds. The geometry and strain of these rings can influence the stability and reactivity of the compound. For example, smaller rings may experience angle strain, while larger rings can accommodate multiple double bonds, leading to various classifications of dienes and polyenes based on their structure.
Recommended video:
Guided course
How to find the root name for cycloalkanes
Related Practice
Textbook Question
3
views
Textbook Question
Predict the products of the following reactions.
(b) cyclopentadiene + anhydrous HCl
4
views
Textbook Question
Predict the products of the following reactions.
(c) 2-methylpropene + NBS, light
3
views
Textbook Question
Phenolphthalein is an acid–base indicator that is colorless below pH 8 and red above pH 8. Explain briefly why the first structure is colorless and the second structure is colored.
1
views
Textbook Question
One milligram of a compound of molecular weight 160 is dissolved in 10 mL of ethanol, and the solution is poured into a 1-cm UV cell. The UV spectrum is taken, and there is an absorption at λmax = 247 nm. The maximum absorbance at 247 nm is 0.50. Calculate the value of e for this absorption.
2
views
Textbook Question
Predict the products of the following reactions.
(a) allyl bromide + cyclohexyl magnesium bromide
2
views