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Ch. 12 - Substitution and Elimination: Reactions of Haloalkanes
Mullins - Organic Chemistry: A Learner Centered Approach 1st Edition
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Not the one you use?Change textbook
Chapter 11, Problem 37a

Practice your electron-pushing skills by drawing a mechanism for the following E2 reactions.
(a) Diagram illustrating an E2 elimination reaction with a chlorine atom and sodium ethoxide in ethanol as reagents.

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Step 1: Identify the substrate (the molecule undergoing the reaction) and the base. In an E2 reaction, the substrate typically contains a leaving group (e.g., a halide) and a β-hydrogen (hydrogen on the carbon adjacent to the carbon bonded to the leaving group). The base will abstract the β-hydrogen.
Step 2: Orient the molecule to ensure that the β-hydrogen and the leaving group are anti-periplanar (i.e., they are in opposite planes and aligned for proper orbital overlap). This geometry is crucial for the E2 mechanism to proceed.
Step 3: Use curved arrows to depict the electron movement. Draw an arrow from the β-hydrogen to the bond between the β-carbon and the α-carbon (the carbon bonded to the leaving group). Simultaneously, draw an arrow from the bond between the α-carbon and the leaving group to the leaving group itself, showing it departing as a leaving ion.
Step 4: Show the formation of the double bond between the α-carbon and the β-carbon as a result of the electron movement. The leaving group is now detached, and the base has abstracted the β-hydrogen.
Step 5: Verify the product structure. The final product should be an alkene formed by the elimination of the β-hydrogen and the leaving group. Ensure that the stereochemistry of the product matches the anti-periplanar geometry of the starting material.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

E2 Mechanism

The E2 mechanism is a type of elimination reaction where a base removes a proton from a β-carbon, leading to the simultaneous departure of a leaving group from the α-carbon. This concerted process results in the formation of a double bond between the α and β carbons. Understanding the stereochemistry and the requirement for anti-periplanar geometry is crucial for accurately depicting E2 mechanisms.
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Electron-Pushing Curved Arrows

Electron-pushing curved arrows are a notation used in organic chemistry to illustrate the movement of electron pairs during chemical reactions. In E2 mechanisms, these arrows show how electrons from the base attack the hydrogen atom, while another arrow indicates the departure of the leaving group. Mastery of this notation is essential for accurately representing reaction mechanisms and understanding electron flow.
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Stereochemistry in E2 Reactions

Stereochemistry plays a significant role in E2 reactions, as the elimination must occur in an anti-periplanar arrangement for optimal overlap of orbitals. This requirement influences the stereochemical outcome of the reaction, often leading to the formation of specific geometric isomers. Recognizing the importance of stereochemistry helps predict the products and understand the reaction's selectivity.
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