cis-3,4-Dimethylcyclobutene undergoes thermal ring opening to form the two products shown. One of the products is formed in 99% yield, the other in 1% yield. Which is which?
Ch. 28 - Pericyclic Reactions
Chapter 25, Problem 41
If isomer A is heated to about 100 °C, a mixture of isomers A and B is formed. Explain why there is no trace of isomer C or D.

Verified step by step guidance1
Analyze the chemical structures of isomers A, B, C, and D. Isomer A and B are structurally similar, differing only in the position of the methyl group and deuterated methyl group. Isomers C and D have different substitution patterns on the aromatic ring.
Consider the reaction conditions: heating to 100 °C. This temperature is sufficient to allow for a reversible equilibrium between isomers A and B, but not for significant bond-breaking or rearrangements that would lead to the formation of isomers C and D.
Examine the mechanism of the isomerization between A and B. The process likely involves a 1,2-shift of the methyl and deuterated methyl groups on the aromatic ring, which is a low-energy pathway under the given conditions.
Explain why isomers C and D are not formed. The formation of C and D would require a complete rearrangement of the substituents on the aromatic ring, which involves breaking and reforming bonds. This is energetically unfavorable under the mild heating conditions provided (100 °C).
Conclude that the equilibrium mixture contains only isomers A and B because the reaction conditions favor simple positional isomerization rather than complex rearrangements that would lead to C and D.
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Isomerism
Isomerism refers to the phenomenon where compounds have the same molecular formula but different structural arrangements. In this case, isomers A and B are structural isomers, meaning they differ in the connectivity of their atoms. Understanding isomerism is crucial for predicting the behavior of compounds under different conditions, such as heating.
Recommended video:
Guided course
Monosaccharides - D and L Isomerism
Thermodynamic Stability
Thermodynamic stability relates to the energy levels of different isomers. Isomers that are lower in energy are more stable and thus favored at equilibrium. The absence of isomers C and D suggests that they are less stable compared to isomers A and B, which can form a mixture when heated, indicating that the reaction favors the formation of the more stable products.
Recommended video:
Guided course
The radical stability trend.
Reaction Conditions
The conditions under which a reaction occurs, such as temperature, can significantly influence the products formed. Heating isomer A to 100 °C likely provides enough energy to facilitate the conversion to isomer B, while isomers C and D may require different conditions or energy levels to form, explaining their absence in the reaction mixture.
Recommended video:
EAS Reactions of Pyridine Example 1
Related Practice
Textbook Question
1
views
Textbook Question
A student found that heating any one of the isomers shown here resulted in scrambling of the deuterium to all three positions on the five-membered ring. Propose a mechanism to account for this observation.
3
views
Textbook Question
Propose a mechanism for the following reaction:
Textbook Question
Explain why two different products are formed from disrotatory ring closure of (2E,4Z,6Z)-octatriene, but only one product is formed from disrotatory ring closure of (2E,4Z,6E)-octatriene.
1
views
Textbook Question
Explain why compound A will not undergo a ring-opening reaction under thermal conditions, but compound B will.
3
views
Textbook Question
b. What would be the product if trans-2-butene were used instead of ethene?
1
views
