Textbook Question
The following 1H NMR spectra are for four compounds, each with molecular formula of C6H12O2. Identify the compounds.
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Ch. 14 - NMR Spectroscopy
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
Chapter 15, Problem 71b
Identify each of the following compounds from its molecular formula and its 1H NMR spectrum:
b. C6H12O
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Verified step by step guidance1
Analyze the molecular formula (C6H12O) to determine the degree of unsaturation. Use the formula: \( \text{Degree of Unsaturation} = \frac{2C + 2 - H + N - X}{2} \), where \( C \) is the number of carbons, \( H \) is the number of hydrogens, \( N \) is the number of nitrogens, and \( X \) is the number of halogens. For C6H12O, calculate \( \text{Degree of Unsaturation} = \frac{2(6) + 2 - 12}{2} = 1 \). This indicates one double bond or a ring in the structure.
Examine the 1H NMR spectrum for key features. Look for the number of signals, their chemical shifts, splitting patterns, and integration values. These provide information about the number of unique hydrogen environments, the types of hydrogens (e.g., alkyl, vinyl, hydroxyl), and their relative quantities.
Identify functional groups based on the molecular formula and NMR data. Since the formula includes oxygen, consider functional groups like alcohols, ethers, or carbonyl-containing groups (e.g., aldehydes or ketones). The degree of unsaturation suggests the possibility of a double bond or a ring structure.
Correlate the chemical shifts in the NMR spectrum with specific hydrogen environments. For example, hydrogens attached to carbons near an oxygen atom (e.g., in alcohols or ethers) typically appear in the range of \( \delta 3.0-4.5 \), while hydrogens on sp2 carbons (e.g., in alkenes) appear in the range of \( \delta 4.5-6.5 \). Analyze splitting patterns to determine connectivity.
Propose a structure that matches the molecular formula, degree of unsaturation, and NMR data. Verify that the structure accounts for all signals in the spectrum, including their chemical shifts, integrations, and splitting patterns. For example, a possible structure for C6H12O could be a cyclic ether (e.g., tetrahydropyran) or an alcohol with a double bond (e.g., 3-hexen-1-ol).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Molecular Formula Interpretation
The molecular formula provides essential information about the number and types of atoms in a compound. For C6H12O, it indicates the presence of six carbon atoms, twelve hydrogen atoms, and one oxygen atom. Understanding how to interpret this formula is crucial for deducing the possible structure and functional groups present in the compound.
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1H NMR Spectroscopy
Proton nuclear magnetic resonance (1H NMR) spectroscopy is a powerful analytical technique used to determine the structure of organic compounds. It provides information about the number of hydrogen atoms in different environments, their chemical shifts, and splitting patterns, which can help identify functional groups and the overall structure of the molecule. Analyzing the NMR spectrum is key to confirming the identity of the compound.
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Isomerism in Organic Compounds
Isomerism refers to the existence of compounds with the same molecular formula but different structural arrangements or spatial orientations. For C6H12O, various isomers can exist, including alcohols, ethers, and ketones. Recognizing the potential isomers is essential for accurately identifying the compound based on its molecular formula and NMR data.
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Related Practice
Textbook Question
Sketch the following spectra that would be obtained for 2-chloroethanol:
d. The proton-coupled 13C NMR spectrum.
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Textbook Question
The following 1H NMR spectra are for four compounds, each with molecular formula of C6H12O2. Identify the compounds.
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Textbook Question
Calculate the amount of energy (in calories) required to flip an 1H nucleus in an NMR spectrometer that operates at 300 MHz.
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Textbook Question
How can 1H NMR be used to prove that the addition of HBr to propene follows the rule that says that the electrophile adds to the sp2 carbon bonded to the most hydrogens?
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Textbook Question
Sketch the following spectra that would be obtained for 2-chloroethanol:
e. The four parts of a DEPT 13C NMR spectrum.